Answer:
Ball Bearing Volume = (4 / 3) * PI * radius ^3
Volume = (4 / 3) * 3.14159265 * (.35)^3
Volume = (4 / 3) * 3.14159265 * 0.042875
Volume = 0.17959438 cc
1 cc of steel = 7.8 g
Volume of 1 kg of steel = 1,000 cc / 7.8 g per cc
1 kg = 128.205 cc
Number of ball bearings we can make = 128.205 / 0.17959438
Equals 713.86
Step-by-step explanation:
Given:
In ΔABC, AB = 5 unit, BC = 2 unit and ∠C = 90°
To find the The value of ∠B.
Formula
By Trigonometric Ratio we know,
Let us take ∠B = θ
With respect to θ, BC is the adjacent side and AB is the hypotenuse.
So,
Hence, the value of ∠B is 66.42°.
1. 3(p+q)=p
3p+3q=p; 3p-p=3q; 2p=q so p=q/2
2. 4a=2b-7
2b=4a+7 so b=(4a+7)/2
when a=3 , b=(12+7)/2=19/2=9.5
3. d=rt; r=d/t
4.( 2x15)+(2xwidth)=90
2x width=90-30
width =60/2=30
90 divided by 40 and the equals 2.25 so it would be 2.25%
Answer:
= 0.16666666666, hope it helps