Hello :
f(x) = <span>a(x-k)²+k....... the point vertex is (h , k )
in this exercice : h = -3 and k = -1 s0 f(x) = a(x+3)²-1
find : a
but f(0)=8
a(0+3)² -1 = 8
9a-1=8
9a =9
a=1
f(x) =(x+3)²-1 =x²+6x+9-1
f(x) = x²+6x+8 .... (</span><span>the quadratic function in standard form )</span>
When a point is reflected across the x-axis the y coordinate becomes negative so when it's reflected across the x-axis the coordinates will be (x,-y).
When a point is reflected across the y-axis the x-coordinate becomes negative so when it's reflected across the y-axis the coordinates become (-x,y).
Answer:
24x^2
Step-by-step explanation:
When expanded (x+2)^4= x^4+8x^3+24x^2+32x+16
The only term that matches with these is 24x^2
The number line represents the fractions
