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Licemer1 [7]
3 years ago
10

Given f(x) = 8x + 25, find x when f(x) = 9.

Mathematics
1 answer:
elixir [45]3 years ago
7 0

Answer:

-2?

Step-by-step explanation:

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I need help on this question 1/2x2x6
Alex
1/2x2x6
=1x6
=6
That's your answer.
3 0
3 years ago
Use the matrix tool to solve the system of equations. Choose the correct ordered pair.3x + 5y = 42 6x + 5y = 54
kobusy [5.1K]
Solutions  

In Matrix we use initially based on systems of linear equations.The matrix method is similar to the method of Elimination as but is a lot cleaner than the elimination method.Solving systems of equations by Matrix Method involves expressing the system of equations in form of a matrix and then reducing that matrix into what is known as Row Echelon Form.<span> 

Calculations 

</span>⇒ <span>Rewrite the linear equations above as a matrix 
</span>
\left[\begin{array}{ccc}3&5&42\\6&5&54\\\end{array}\right] 

⇒  Apply to Row₂ : Row₂ - 2 <span>Row₁ 
</span>
\left[\begin{array}{ccc}3&5&42\\0&-5&-30\\\end{array}\right] 

⇒ <span>Simplify rows
</span>
\left[\begin{array}{ccc}3&5&42\\0&1&6\\\end{array}\right] 

Note: The matrix is now in echelon form.
<span>The steps below are for back substitution. 
</span>
⇒ Apply to Row₁<span> : Row</span>₁<span> - </span>5 Row₂ 

\left[\begin{array}{ccc}3&0&12\\0&1&6\\\end{array}\right] 

⇒ <span>Simplify rows 
</span>
\left[\begin{array}{ccc}1&0&4\\0&1&6\\\end{array}\right] 

⇒ <span>Therefore, 
</span>
x=4&#10;&#10;y = 6
<span> 

 
</span>

5 0
2 years ago
If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe
Natalka [10]

Answer:

They encircle the planet 3.76\times 10^{11} times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

If we line up the particles the distance they could cover is:

15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}

Circumference in meters:

40,076km\times \frac{1000m}{1km}=40,076,000 m

Therefore,

\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

Hence, they encircle the planet 3.76\times 10^{11} times.

8 0
3 years ago
What is the slope of the line passing through the points (−3, 4) and (4, −1)?
Igoryamba
Note:
The slope of a straight line passing through the points (x₁, y₁) and (x₂, y₂) is 
m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

The two given points are (-3,4) and (4,-1). Therefore the slope is
m= \frac{-1-4}{4-(-3)} = \frac{-5}{7}

Answer: - \frac{5}{7}

3 0
3 years ago
Solve for x<br> -5(2x+1)-2x-2=17
inna [77]

-5(2x+1)-2x-2=17
first, distribute
-10x-5-2x-2=17
combine like terms
-12x-7=17
get the x alone, eliminate the constant
-12x=24
divide out the -12 to get the x alone.
x=-2
4 0
2 years ago
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