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2 years ago

12

Please help me! : find the median please

2 answers:

Yuri [45]2 years ago

6 0

To get the median you add the numbers and then divide by the number of numbers in the data

REY [17]2 years ago

5 0

Answer:

#2. 3, #3. 9, #4. 6.2,$ 5. 9,# 6. 16, $7. 4, and #8. 3

Step-by-step explanation:

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Go to Meet and type this password b e y i s q s t u k <br> but no spaces

belka [17]

Answer:

for what tho lol

Step-by-step explanation:

5 0

2 years ago

If your insurance plan is $15,000 and you pay for 20%, how much do you

podryga [215]

Answer: 250

Step-by-step explanation:

20% of 15,000 is 3,000

3,000/12=250

7 0

3 years ago

Read 2 more answers

Finding the inverse of the function x^3+3x+1 is beyond the scope of this course. Nevertheless, you should be able to use your kn

slega [8]

Step-by-step explanation:

${x}^{3} + 3x + 1 = 1 = = = > \\ {x}^{3} + 3x = 0 = = = > \\ x({x}^{2} + 3) = 0 \\ x = 0 \: or \\ {x}^{2} + 3 = 0 = = = > \\ {x}^{2} = - 3 = = = > x 1= \sqrt{ - 3} \: or \: i \sqrt{3} \\ x2 = - \sqrt{ - 3} = = = > x2 = - i \sqrt{3}$

${x}^{3} + 3x + 1 = 5 = = = > \\ {x}^{3} + 3x - 4 = = = > \\ (x - 1)( {x}^{2} + x + 4) = 0 = = = > \\ x - 1 = 0 = = > x1 = 1 \\ {x}^{2} + x + 4 = 0 = = = > \\ x2 = - 1 + i \sqrt{3} \\ x3 = - 1 - i \sqrt{3}$

${x}^{3} + 3x + 1 = 3 = = = > \\{ x}^{3} + 3x - 2 = 0 = = = > x = 0.6$

4 0

2 years ago

HELP PLZ DUE RN BRAINIEST TO WHOEVER RIGHT

Y_Kistochka [10]

Answer:

$x = \dfrac{2}{5} + \dfrac{\sqrt{14}}{5}$ or $x = \dfrac{2}{5} - \dfrac{\sqrt{14}}{5}$

Step-by-step explanation:

$5x^2 - 2 = 4x$

$5x^2 - 4x - 2 = 0$

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$x = \dfrac{-(-4) \pm \sqrt{(-4)^2 - 4(5)(-2)}}{2(5)}$

$x = \dfrac{4 \pm \sqrt{16 + 40}}{10}$

$x = \dfrac{4 \pm 2\sqrt{14}}{10}$

$x = \dfrac{2 \pm \sqrt{14}}{5}$

$x = \dfrac{2}{5} + \dfrac{\sqrt{14}}{5}$ or $x = \dfrac{2}{5} - \dfrac{\sqrt{14}}{5}$

4 0

2 years ago

Read 2 more answers

In his motorboat, Bill Ruhberg travels upstream at top speed to his favorite fishing spot, a distance of 264 mi, in 6 hr. Re

Kobotan [32]

Answer:

The values are $x = 46 miles /hr$

$y = 4 \ miles / hr$

Step-by-step explanation:

From the question we are told that

The distance covered is d = 264 miles

The time taken is $t_1 = 6 hours$

The time taken for the return trip is $t_2 = 5.5 \ hours$

Generally during the trip toward fishing spot , the velocity is mathematically represented as

$v_t = \frac{d}{t_1 } = x - y$

=> $v_t = \frac{264}{6 } = x - y$

=> $x - y = 44 \cdots 1$

Generally during the return trip , the velocity is mathematically represented as

$v_r = \frac{d}{t_2} = x+ y$

=> $v_r = \frac{264}{5.5} = x+ y$

=> $48 = x+ y\cdots 2$

add equation 1 and 2

$2x = 92$

=> $x = 46 miles /hr$

substituting this into equation 1

$46 - y = 44 \cdots 1$

=> $y = 4 \ miles / hr$

5 0

3 years ago