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2 years ago

Please help me! : find the median please

Mathematics

2 answers:

Yuri [45]2 years ago

6 0

To get the median you add the numbers and then divide by the number of numbers in the data

REY [17]2 years ago

5 0

Answer:

#2. 3, #3. 9, #4. 6.2,$ 5. 9,# 6. 16, $7. 4, and #8. 3

Step-by-step explanation:

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What is the value of 3ab+<br>5b - 6 when a = - 1and b = 3

Fantom [35]

Answer:

the answer is 0

4 0

3 years ago

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4. In slope-intercept form, what is the equation of a line perpendicular toy - 2x + 7 that passes

Phoenix [80]

Answer:

y = (-1/2)x + 21/2

Step-by-step explanation:

Given equation:

y - 2x + 7

Coordinates = (5,8)

Find:

Perpendicular equation

Computation:

y = mx + c

y - 2x + 7

y = 2x - 7

So,

m = 2

The negative reciprocal of 2 is -1/2

So,

For,

Coordinates = (5,8)

y = mx + c

8 = (-1/2)(5) + c

8 = -5/2 + c

c = 8 + 5/2

c = 21 /2

So,

y = mx + c

y = (-1/2)x + 21/2

7 0

3 years ago

Item 20 A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the sc

siniylev [52]

Answer:

The ratio of the area of the school banner to the area of the sign is <u>1944 cubic inches : 192.61 cubic inches.</u>

Step-by-step explanation:

Given:

A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the school banner and has a length of 17 inches.

Now, to find the ratio of the area of the school banner to the area of the sign.

Dimensions of school banner :

Length = 54 inches.

Width = 36 inches.

Dimension of school sign:

Length = 17 inches.

So, to we find the width of sign by using cross multiplication method:

Let the width be $x.$

So, 54 is equivalent to 36.

Thus, 17 is equivalent to $x.$

$\frac{54}{36} =\frac{17}{x}$

By cross multiplying we get:

$54x=612$

Dividing both sides by 54 we get:

$x=11.33\ inches.$

Thus, the width of sign = 11.33 inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

Area of the school banner : Area of the school sign.

= $54\times 36:17\times 11.33$

= $1944:192.61$

Therefore, the ratio of the area of the school banner to the area of the sign is 1944 cubic inches : 192.61 cubic inches.

6 0

3 years ago

Read 2 more answers

A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading

Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

So, Force = 6089 * 4.4482N

Force = 27085.09 N

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0

4 years ago

Please help with via math I suck at math so plz help... will give brainiest to the person I think gave the best answer.

kati45 [8]

The answer is C because 80-28= 52.

4 0

3 years ago

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