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Naddika [18.5K]
3 years ago
9

The restriction enzyme bamhi recognizes the dna sequence ggatcc and always cuts between the two g nucleotides. how many bases lo

ng is the sticky end of a dna molecule that has been cut with bamhi?
Biology
1 answer:
vladimir1956 [14]3 years ago
8 0

The correct answer is four base pairs.

BamHI is endonuclease meaning that it has the ability to cut DNA at specific target site. The recognition sequence of BamHI is 5'-GGATCC-3 and it cleaves it after the first G. Sticky ends are formed as a result of that cleavage remaining a four-base 5' overhang in one molecule and a complementary 5' overhang in the other. These ends are can be joined back together by an enzyme called ligase.


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