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Nataliya [291]
3 years ago
15

Assume that x is a char variable that has been declared and already given a value. Write an expression whose value is true if an

d only if x is an hexadecimal (Base 16) digit (0-9 plus A-F or a-f).
Computers and Technology
1 answer:
maria [59]3 years ago
8 0

Answer:

^[A-Fa-f0-9]+$

Explanation:

The hexadecimal (Base 16) can contain 0-9, A-F, a-f and any of these can be the part of the Hexadecimal base 16 code.

In python we have the re.match function, and the syntax is as below:

re.match(pattern, string, flag=0). And we can use this function to check whether the entered char variable is a regex or not. Like:

re.match(pattern,x, flag=0)

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Answer:

ll and lll

Explanation:

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Please help me I don’t know what to do
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Read 2 more answers
Find the root using bisection method with initials 1 and 2 for function 0.005(e^(2x))cos(x) in matlab and error 1e-10?
frutty [35]

Answer:

The root is:

c=1.5708

Explanation:

Use this script in Matlab:

-------------------------------------------------------------------------------------

function  [c, err, yc] = bisect (f, a, b, delta)

% f the function introduce as n anonymous function

%       - a y b are the initial and the final value respectively

%       - delta is the tolerance or error.

%           - c is the root

%       - yc = f(c)

%        - err is the stimated error for  c

ya = feval(f, a);

yb = feval(f, b);

if  ya*yb > 0, return, end

max1 = 1 + round((log(b-a) - log(delta)) / log(2));

for  k = 1:max1

c = (a + b) / 2;

yc = feval(f, c);

if  yc == 0

 a = c;

 b = c;

elseif  yb*yc > 0

 b = c;

 yb = yc;

else

 a = c;

 ya = yc;

end

if  b-a < delta, break, end

end

c = (a + b) / 2;

err = abs(b - a);

yc = feval(f, c);

-------------------------------------------------------------------------------------

Enter the function in matlab like this:

f= @(x) 0.005*(exp(2*x)*cos(x))

You should get this result:

f =

 function_handle with value:

   @(x)0.005*(exp(2*x)*cos(x))

Now run the code like this:

[c, err, yc] = bisect (f, 1, 2, 1e-10)

You should get this result:

c =

   1.5708

err =

  5.8208e-11

yc =

 -3.0708e-12

In addition, you can use the plot function to verify your results:

fplot(f,[1,2])

grid on

5 0
3 years ago
If i find an image and copy and paste it into Paint.
Leokris [45]

Answer:

Lossy image formats will remove data during compression as a trade off for lower storage occupation. Lossless data formats will not remove data during compression, resulting in higher quality but also higher storage occupation.

Graphic Artists will almost always use lossless due to it delivering the highest quality image possible.

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You can increase your efficiency by using your e-mail program's spell checker because it eliminates the need for you to proofrea
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