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MrMuchimi
3 years ago
5

If i find an image and copy and paste it into Paint.

Computers and Technology
1 answer:
Leokris [45]3 years ago
8 0

Answer:

Lossy image formats will remove data during compression as a trade off for lower storage occupation. Lossless data formats will not remove data during compression, resulting in higher quality but also higher storage occupation.

Graphic Artists will almost always use lossless due to it delivering the highest quality image possible.

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Match the appropriate color mode with the correct definition
Gemiola [76]

Answer:

1.RGB: Best for projects intended to be used on the web or video

Explanation:

On websites or making project RGB combination of colors is used. This combination of colors is used to store images in electronic components.

2. CMYK: best for professional printing projects using process colors

Explanation:

Printing professional use CMYK combinations of color for better printing results.

3.) indexed:The only colors saved are the colors used in the image

To manage digital images we use Indexed mode of colors.

Explanation:

4.) bitmap: uses black and white

Explanation:

bitmap is the combination of the black and white colors. As the images are large in size so that, to reduce the size of the image we store image in bitmap to reduce the size.

5.) gray scale: uses different shades of grey

Explanation:

The different shades of gray colors are found in the gray scale. These shades are used to produce images.

4 0
3 years ago
Implement a Java program that creates math flashcards for elementary grade students. User will enter his/her name, the type (+,
jeka57 [31]

import java.util.Scanner;

public class JavaApplication44 {

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       System.out.print("Enter you name: ");

       String name = scan.nextLine();

       System.out.print("Enter your operation (+,-,*,/): ");

       String operator = scan.nextLine();

       System.out.print("Enter the range of the problems: ");

       int ran = scan.nextInt();

       System.out.print("Enter number of problems: ");

       int problems = scan.nextInt();

       int score = 0;

       for (int i = 1; i <= ran; i++){

           int first = (int)(Math.random()*ran);

           int sec = (int)(Math.random()*ran);

           System.out.print("Problem #"+i+": "+first + " "+operator+" "+sec+" = ");

           int ans = scan.nextInt();

           if (operator.equals("+")){

               if (ans == first + sec){

                   System.out.println("Correct!");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first+sec));

               }

           }

           else if(operator.equals("-")){

               if (ans == first - sec){

                   System.out.println("Correct");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first - sec));

               }

           }

           else if (operator.equals("*")){

               if (ans == first * sec){

                   System.out.println("Correct");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first * sec));

               }

           }

           else if (operator.equals("/")){

               if (ans == first / sec){

                   System.out.println("Correct");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first / sec));

               }

           }

           

       }

       System.out.println(name+", you answered "+score+" questions correctly.");

   }

   

}

I hope this helps!

8 0
3 years ago
When resizing images or objects in a presentation, why should a user not utilize the sizing handles in the middle of the sides o
Volgvan

Answer:

b. It will resize the image but not maintain aspect ratio

Explanation: is correct. post protected

7 0
2 years ago
Give an example of a function from N to N that is: Hint: try using absolute value, floor, or ceiling for part (b). (a) one-to-on
Naily [24]

Answer:

Let f be a function  

a) f(n) = n²  

b) f(n) = n/2  

c) f(n) = 0  

Explanation:  

a) f(n) = n²  

This function is one-to-one function because the square of two different or distinct natural numbers cannot be equal.  

Let a and b are two elements both belong to N i.e. a ∈ N and b ∈ N. Then:

                               f(a) = f(b) ⇒ a² = b² ⇒ a = b  

The function f(n)= n² is not an onto function because not every natural number is a square of a natural number. This means that there is no other natural number that can be squared to result in that natural number.  For example 2 is a natural numbers but not a perfect square and also 24 is a natural number but not a perfect square.  

b) f(n) = n/2  

The above function example is an onto function because every natural number, let’s say n is a natural number that belongs to N, is the image of 2n. For example:

                               f(2n) = [2n/2] = n  

The above function is not one-to-one function because there are certain different natural numbers that have the same value or image. For example:  

When the value of n=1, then

                                  n/2 = [1/2] = [0.5] = 1  

When the value of n=2 then  

                                   n/2 = [2/2] = [1] = 1  

c) f(n) = 0

The above function is neither one-to-one nor onto. In order to depict that a function is not one-to-one there should be two elements in N having same image and the above example is not one to one because every integer has the same image.  The above function example is also not an onto function because every positive integer is not an image of any natural number.

5 0
3 years ago
When using a spreadsheet, the expression =d8-d17 is called a ________?
raketka [301]
A big fat piece of poop
6 0
3 years ago
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