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3 years ago

Please show your work

Mathematics

1 answer:

HACTEHA [7]3 years ago

4 0

250 = 167.93 + x

[She needs $250, she has $167.93, and she needs x more. x represents the amount of money she still needs in order to get 250]

250 = 167.93 + x Subtract 167.93 on both sides

250 - 167.93 = 167.93 + x - 167.93

250 - 167.93 = x

82.07 = x

She needs $82.07 more

Or you could have done:

250 - 167.93 = 82.07

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Matte Satin Glossy Total

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2 years ago

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3 years ago

Expand using the properties and rules for logarithms

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Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

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2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

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4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

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Answer:

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Step-by-step explanation:

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