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Kisachek [45]
2 years ago
7

What are the two LARGEST angles for question one? Show work if possible

Mathematics
1 answer:
Brums [2.3K]2 years ago
4 0
In a triangle, the measure of angles is in the same order of size as the order of the lengths of the opposite sides.

The largest angle is opposite the longest side.
The smallest angle is opposite the smallest side.
The mid-sized angle is opposite the mid-sized side.

The longest side measures 6 ft. The angle opposite that side is angle M.
Angle M is the largest angle.

The second longest side measures 5.5 ft. The angle opposite that side is angle N. Angle N is the second largest angle.

Answer: Angles M and N.
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given that (0,-7) is on the graph of f(x), find the corresponding point of point for the function f(x+2)
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The graph of f(x+2) is the graph of f(x) moved 2 units to the left. The corresponding point is ...
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step by step explanation:

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M∠1 = 80 – x; and
Burka [1]

Answer:

10

Step-by-step explanation:

<em>m∠</em>2 and <em>m∠</em>1 are congruent by the Corresponding Angles Theorem; we set both expressions equal to each other:

[80 - x]° = [90 - 2x]°

+ x° + x°

______________

80° = [90 - x]°

-90° - 90°

__________

−10° = [−x]°

10° = x

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6 0
2 years ago
Please help! its due today!!
nekit [7.7K]

Answer:

14

Step-by-step explanation:

a=1

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3 0
2 years ago
1. Trapezoid BEAR has a height of 8.5 centimeters and parallel bases that measure 6.5 centimeters and 11.5 centimeters. To the n
e-lub [12.9K]
<h3>Given</h3>

1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.

2) Regular pentagon PENTA with side lengths 9 m

<h3>Find</h3>

The area of each figure, rounded to the nearest integer

<h3>Solution</h3>

1) The area of a trapezoid is given by

... A = (1/2)(b1 +b2)h

... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77

The area of BEAR is about 77 cm².

2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...

... A = (1/2)ap

... A = (1/2)(s/(2tan(180°/n)))(ns)

... A = (n/4)s²/tan(180°/n)

We have a polygon with s=9 and n=5, so its area is

... A = (5/4)·9²/tan(36°) ≈ 139.36

The area of PENTA is about 139 m².

6 0
2 years ago
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