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3 years ago

What is the answer if you factor completely

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

3 0

Answer:

Your correct and final answer is (9+x^6) (3+x^3) (3-x^3)

Hope this helps!!!

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Which decimal is closest in value to 9/20

yan [13]

Answer:

0.45

Step-by-step explanation:

9/20 is the same as 0.45

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What is the quotient of 99 divided by 9081

Nataliya [291]

the answer is0.0101010101

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3 years ago

HELP I NEED THIS NOW!!!!

borishaifa [10]

Answer:

So, The area of trapezoid = 4.413 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and m∠NMK = 65° , OT = R

So, m∠MNP = 180° - 65° = 115° ⇒ supplementary interior angles.

Join ON ⇒ ΔOSN is a right triangle at S.

And NP, NM are tangents to the circle

So, ON bisects the angle ∠MNP = ∠MNS

∠ONS = (∠MNS)/2 = 115/2 = 57.5°

So, tan (∠ONS) = OS/NS = R/(NS)

NS = R/tan (∠ONS)=R/(tan 57.5°) ≈ 0.637 R

∴ NP = 2 * NS = 1.274 R

Construct: a line parallel to ST from N to line MK

let the intersection point be Q ⇒ NQ = 2R

So, Δ NQM is a right triangle at Q

tan (∠NMQ) = tan 65 = NQ/MQ

MQ = NQ/(tan 65)=2R/tan 65 ≈ 0.932 R

∴ MK = 2 MT = 2 (MQ + QT) ⇒ QT = NS

= 2 (MQ + NS ) = 2( 0.932 R + 0.637 R) = 2 * 1.569 R

∴ MK = 3.139 R

Now, area of trapezoid = height × (sum of parallel sides/ 2)

Area = ST * (NP + MK)/2

= 2R * (1.274 R + 3.139 R) / 2

= 2R * 4.413 R /2

= 4.413 R²

So, The area of trapezoid = 4.413 R²

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What is the largest domain?

Elenna [48]

The largest domain for this is answer C [-1,1]

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What is the following sum? 2 (RootIndex 3 StartRoot 16 x cubed y EndRoot) 4 (RootIndex 3 StartRoot 54 x Superscript 6 Baseline y

san4es73 [151]

Equivalent expressions are expressions that have the same value, and can be used interchangeably.

The result of the sum $2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})$ is $4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})$

The expression is given as:

$2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})$

Rewrite the expression as:

$2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (\sqrt[3]{2^4x^3y}) + 4 (\sqrt[3]{3^3 \times 2x^6y^5})$

Evaluate the roots

$2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (2x\sqrt[3]{2y}) + 4 (3x^2y\sqrt[3]{2y^2})$

Open the brackets

$2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 4x\sqrt[3]{2y} + 12x^2y\sqrt[3]{2y^2})$

The above expression cannot be further simplified.

Hence, the result of the sum $2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})$ is $4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})$

Read more about equivalent expressions at:

brainly.com/question/2972832

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