The total number of problems she needs to grade is 6.
by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
Answer:
It does
Step-by-step explanation:
It does have a proportional relationship because if you try to find the relationship between the first two inputs and outputs, you can find that it is 21 (1 to 21, 21 divided by 1 would be 21) then if you use that relationship with the other numbers (times 21) you would get the same answer. For example in the second one, the two numbers are 2 and 42, 2 times 21 would equal 42. The next one would be 3 times 21 to equal 63 and etc.
Hope this Helps!!
Answer:
quadrant 1.
Step-by-step explanation:
A:(9,3)
B:(7,5)
C:(5,2)
Hope this helped you.
Answer:
[-1, ∞ )
Step-by-step explanation:
The use of parentheses is essential here. I am assuming that you meant:
y=√(x-5) - 1
Note that √(x-5) has the range [0, ∞ ). The domain is [5, ∞ ).
Thus, y=√(x-5) - 1 has the range [-1, ∞ )
