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castortr0y [4]
2 years ago
9

ms shah grades 3402 math problems during 5th period this is 54% of the total number of problems she need to grade what is the to

tal number of problems she needs to grade
Mathematics
1 answer:
olga_2 [115]2 years ago
6 0
The total number of problems she needs to grade is 6.
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7in * 1ft/0.5in = 14ft
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option 1 drop down are: even-odd identity, quotient identity, Pythagorean identity, double-number identity.option 2 drop down ar
motikmotik

Answer:

The equation is given below as

\frac{\cos2x}{\cos x}=\cos x-\sin x\tan x

Step 1:

We will work on the left-hand side, we will have

\begin{gathered} \cos x-\sin x\tan x \\ \text{recall that,} \\ Quoitent\text{ identity is} \\ \tan x=\frac{\sin x}{\cos x} \end{gathered}

By substituting the identity above, we will have

\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x}=\cos x-\frac{\sin^2x}{\cos x} \\  \end{gathered}

Here, we will make use of the quotient identity

Step 2:

By writings an expression, we will have

\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x} \\ \cos x-\sin x\tan x=\frac{\cos^2x-\sin^2x}{\cos x} \end{gathered}

Here, we will use the definition of subtraction

\cos x-\frac{\sin^2x}{\cos x}

Step 3:

We will apply the double number identity given below

\begin{gathered} \cos 2\theta=\cos (\theta+\theta)=\cos ^2\theta-\sin ^2\theta \\ \cos 2x=cos(x+x)=\cos ^2x-\sin ^2x \end{gathered}

By applying this, we will have

\frac{\cos^2x-\sin^2x}{\cos x}=\frac{\cos2x}{\cos x}

Here, we will use the double number identity

\frac{\cos^2x-\sin^2x}{\cos x}

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1 year ago
Evaluate the expression a divided by b for a=24 and b=3
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The answer is 8...............
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A book of stamps costs $9.80 $ 9 . 80 . The expression 9.8 9 . 8 n represents the price of one stamp. What does the variable n r
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Answer: n represents the amount a stamp cost

Step-by-step explanation:


7 0
3 years ago
Help me please !!!!
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Answer:

BC = 10

Step-by-step explanation:

BC = BD - CD

BC = 14 - 4

BC = 10

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3 years ago
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