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2 years ago

10

Maathhhhh tingssssss

2 answers:

DIA [1.3K]2 years ago

7 0

Will you give me brainliest if I solve this?

matrenka [14]2 years ago

5 0

Answer:

not sure sorry

Step-by-step explanation:

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Jerry ran 3/4 of a mile in 1/8 of an hour. What was Jerry's rate of speed in miles per hour?

yarga [219]

Answer:

6 miles per hour

Step-by-step explanation:

we'll set up the problem like this:

3/4 mi = 1/8 hr

now multiply each side by 8:

24/4 mi = 1 hr

simplify:

6 mi = 1 hr

3 0

3 years ago

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A dolphin is 9 feet below the surface of the ocean. If its position can be recorded as −9 feet, what would the position of 0 rep

bearhunter [10]

Answer:

the sea line

I am guessing

Step-by-step explanation:

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3 years ago

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Translate: The quotient of a number t and 7, plus 2, is -4 ?

Tems11 [23]

The quotient of a number t and 7, plus 2, is -4 ?

t/7 +2 = -4

4 0

2 years ago

mr.browns salary is 32,000 and imcreases by $300 each year, write a sequence showing the salary for the first five years when wi

chubhunter [2.5K]

Hello!

We have the following data:

a1 (first term or first year salary) = 32000

r (ratio or annual increase) = 300

n (number of terms or each year worked)

We apply the data in the Formula of the General Term of an Arithmetic Progression, to find in sequence the salary increases until it exceeds 34700, let us see:

formula:

$a_n = a_1 + (n-1)*r$

* second year salary

$a_2 = a_1 + (2-1)*300$

$a_2 = 32000 + 1*300$

$a_2 = 32000 + 300$

$\boxed{a_2 = 32300}$

* third year salary

$a_3 = a_1 + (3-1)*300$

$a_3 = 32000 + 2*300$

$a_3 = 32000 + 600$

$\boxed{a_3 = 32600}$

* fourth year salary

$a_4 = a_1 + (4-1)*300$

$a_4 = 32000 + 3*300$

$a_4 = 32000 + 900$

$\boxed{a_4 = 32900}$

* fifth year salary

$a_5 = a_1 + (5-1)*300$

$a_5 = 32000 + 4*300$

$a_5 = 32000 + 1200$

$\boxed{a_5 = 33200}$

We note that after the first five years, Mr. Browns' salary has not yet surpassed 34700, let's see when he will exceed the value:

* sixth year salary

$a_6 = a_1 + (6-1)*300$

$a_6 = 32000 + 5*300$

$a_6 = 32000 + 1500$

$\boxed{a_6 = 33500}$

* seventh year salary

$a_7 = a_1 + (7-1)*300$

$a_7 = 32000 + 6*300$

$a_7 = 32000 + 1800$

$\boxed{a_7 = 33800}$

* eighth year salary

$a_8 = a_1 + (8-1)*300$

$a_8 = 32000 + 7*300$

$a_8 = 32000 + 2100$

$\boxed{a_8 = 34100}$

* ninth year salary

$a_9 = a_1 + (9-1)*300$

$a_9 = 32000 + 8*300$

$a_9 = 32000 + 2400$

$\boxed{a_9 = 34400}$

* tenth year salary

$a_{10} = a_1 + (10-1)*300$

$a_{10} = 32000 + 9*300$

$a_{10} = 32000 + 2700$

$\boxed{a_{10} = 34700}$

we note that in the tenth year of salary the value equals but has not yet exceeded the stipulated value, only in the eleventh year will such value be surpassed, let us see:

* eleventh year salary

$a_{11} = a_1 + (11-1)*300$

$a_{11} = 32000 + 10*300$

$a_{11} = 32000 + 3000$

$\boxed{\boxed{a_{11} = 35000}}\end{array}}\qquad\checkmark$

Respuesta:

In the eleventh year of salary he will earn more than 34700, in the case, this value will be 35000

________________________

¡Espero haberte ayudado, saludos... DexteR! =)

7 0

2 years ago

What expression is factor of 6x^3-13x^2-28x

Harrizon [31]

The answer is $x(2x-7)(3x+4)$

Hope this helps!

8 0

3 years ago

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