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2 years ago

X^+3x-10=0 what solution set represents the value of x

Mathematics

2 answers:

7nadin3 [17]2 years ago

4 0

$x^2+3x-10=0\\
x^2-2x+5x-10=0\\
x(x-2)+5(x-2)=0\\
(x+5)(x-2)=0\\
x=-5 \vee x=2
$

Stolb23 [73]2 years ago

3 0

$\displaystyle x^2+3x-10=0\\\\x_{1,2}= \frac{-3\pm \sqrt{3^2-4\cdot 1\cdot (-10)} }{2\cdot 1}= \frac{-3\pm \sqrt{49} }{2}= \frac{-3\pm7}{2}=2, (-5)$

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Answer:

1) The factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) The factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

Step-by-step explanation:

1) Factor : $x^2-3x+2=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

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So, factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) Factor: $x^2+2x-8=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

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We can break them as (4x)( -2x)

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