Question

X^+3x-10=0 what solution set represents the value of x

Answer 1

$x^2+3x-10=0\\ x^2-2x+5x-10=0\\ x(x-2)+5(x-2)=0\\ (x+5)(x-2)=0\\ x=-5 \vee x=2$

Answer 2

$\displaystyle x^2+3x-10=0\\\\x_{1,2}= \frac{-3\pm \sqrt{3^2-4\cdot 1\cdot (-10)} }{2\cdot 1}= \frac{-3\pm \sqrt{49} }{2}= \frac{-3\pm7}{2}=2, (-5)$