Answer:
Correct to 1dp
127.3 cm = 127.0 cm
86.5 cm = 87.0 cm
Upper limits:
127.0 cm = 127.05 cm
87.0 cm = 87.05 cm
Lower Limits:
127.0 cm = 126.95 cm
87.0 cm = 86.95 cm
upper limit of perimeter of rectangle:
P = 2(l+w)
= 2(127.05 + 87.05)
= 2(214.1)
= 428.2 cm
lower limit of perimeter of rectangle:
P = 2(l+w)
= 2(126.95 + 86.95)
= 2(213.9)
= 427.8 cm
therefore;
Answer:
yes
Step-by-step explanation:
Answer:
Graph A has infinite solutions, Graph B has one solution, and Graph C has no solutions
Step-by-step explanation:
Answer:
(-8,8)
Step-by-step explanation:
Answer:
Step-by-step explanation:
GH : √(8-4)^2 + (2-5)^2 = √16+9 = √25 = 5
HI : √(-6-2)^2 + (2-8)^2 = √64+36 = √100 = 10
IJ : √(-2-2)^2 + (-3+6)^2 = √16 + 9 = √25 = 5
JH : √(-2-4)^2 + (-3-5)^2 = √36 + 64 = √100 = 10
Slope of the line that contains GH
(2-5)/(8-4) = -3/4
Slope of the line that contains HI
(-6-2) / (2-8) = 8/6 = 4/3
I calculated the distance between points. Thanks to that I noticed that the opposite sides are congruent, so the quadrilateral can be a rectangle or a parallelogram. So I found the slope of the lines that contain two consecutive sides and I discovered that are perpendicular. So the quadrilateral is a rectangle because its angles are all of 90 degrees
