Let u = x.lnx, , w= x and t = lnx; w' =1 ; t' = 1/x

f(x) = e^(x.lnx) ; f(u) = e^(u); f'(u) = u'.e^(u)

let' find the derivative u' of u
u = w.t
u'= w't + t'w; u' = lnx + x/x = lnx+1

u' = x+1 and f'(u) = ln(x+1).e^(xlnx)

finally the derivative of f(x) =ln(x+1).e^(x.lnx) + 2x

4 0

3 years ago

In circle O, the length of radius OL is 6 cm and the length of arc LM is 6.3 cm. The measure of angle MON is 75°

djyliett [7]

Answer:

14.2cm

Step-by-step explanation:

Complete question:

In circle O, the length of radius OL is 6 cm and the length of arc LM is 6.3 cm. The measure of angle MON is 75°.

Rounded to the nearest tenth of a centimeter, what is the length of arc LMN?

Find the diagram attached

arc LN= arc LM + arc MN

First we need to get the arc MN

length of an arc = theta/360 * 2πr

length of arc MN = 75/360 * 2(3.14)(6)

length of arc MN = 0.20833*37.68

length of arc MN = 7.85

Hence;

arc LN = 6.3 + 7.85

arc LN = 14.15cm

Hence the length of arc LN is 14.2cm

8 0

3 years ago

.736 rounded to the nearest hundredth

Ne4ueva [31]

.74 is the answer rounded to nearest hundredth.

6 0

4 years ago