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Tcecarenko [31]
4 years ago
6

Is 52800 cm greater than i kilometer

Mathematics
1 answer:
Valentin [98]4 years ago
6 0
79. Is 52 800 centimeters greater than 1 kilometer? According to the unit of conversion in every 1 kilometer, there is a total of 100 000 centimeters. Now, the given value of centimeters is equals to 52 800 => 1 km = 100 000 cm => 52 800 cm is less than the value of 100 000 cm which is equivalent to 1 km. Thus, the given is not correct. 52 800 cm is less than 1 kilometer.
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Find the equation for 4x/5=1/3(2x-15)
tia_tia [17]
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4x / 5= ( 2x - 15 ) / 3
4x × 3 = 5 ( 2x - 15 )
12x = 10x - 75
12x - 10x = - 75
2x = - 75
x = - 75 / 2
x = - 37.5
7 0
4 years ago
Let cos A = <img src="https://tex.z-dn.net/?f=1%2F%5Csqrt%7B10%7D" id="TexFormula1" title="1/\sqrt{10}" alt="1/\sqrt{10}" align=
Rzqust [24]
Umm i’m sorry but what is the question here .

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3 0
2 years ago
X/(4.2 )= -3 <br><br><br><br><br> Theres no choices
Ksivusya [100]

Answer:

-1.40

Step-by-step explanation:

The answer is -1.40 (negative 1 and 2/5) because....

The number would have to be a mixed number.

The number would also have to be a negative.

5 0
3 years ago
2) How is first aid provided to victims of disasters who are injured ?​
skelet666 [1.2K]

{\texttt{\huge{\purple{ANSWER :-}}}}

First aids could be provided to the victims of the disasters which consists mostly :

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5 0
4 years ago
Read 2 more answers
a manufacturer of nickel-cadmium batteries recommends storing the batteries at temperatures ranging from -20 degrees celsius to
Svetllana [295]

Given that the manufacturer recommends storing the batteries at temperatures ranging from -20 degrees celsius to 45 degrees celsius, you can identify that the minimum temperature they can be stored is:

-20\text{ \degree}C

And the maximum temperature they can be stored is:

45\text{ \degree}C

Let be "T" the temperature (in degrees Fahrenheit) at which the batteries can be stored.

You need to convert the minimum and maximum temperature from Degrees Celsius to Degrees Fahrenheit using this formula:

D.\text{ }Fahrenheit=(D.\text{ }Celsius\cdot\frac{9}{5})+32

Then, you get:

D.\text{ }Fahrenheit=(-20\cdot\frac{9}{5})+32=-4D.\text{ }Fahrenheit=(45\cdot\frac{9}{5})+32=113

Therefore, you can write the following inequality to represents describe "T":

-4\leq T\leq113

Hence, the answer is:

-4\leq T\leq113

8 0
1 year ago
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