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Ket [755]
3 years ago
10

Domain And Range, Best answer will get brainliest

Mathematics
1 answer:
MrMuchimi3 years ago
7 0

Answer:

Domain is all the values that go into a function, and range are the values that come out of that function

Step-by-step explanation:

A value is an integer, so when you have an INPUT (your domain) that makes a line/slope, an OUTPUT (your range) will be your outcome, aka your answer

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Distance, Midpoint, Circles - What is the equation of the circle? WILL GIVE BRAINLIEST!
elixir [45]

Answer:

(x-4)^2 + (y-3)^2 =8

Step-by-step explanation:

The midpoint of the diameter is (6+2)/2= 4, (5+1)/2 = 3

(4,3)

The radius is the distance from the midpoint to an endpoint

This is 2sqrt(8)

So the equation is

(x-4)^2 + (y-3)^2 =8

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3 years ago
Two mechanics worked on a car. The first mechanic worked for 5 hours, and the second mechanic worked for 15 hours. Together they
AleksAgata [21]
6x+8y=1,200and 150adults
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3 years ago
A field is a rectangle with a perimeter of 1220 feet. The length is 100 feet more than the width. Find the width and length of t
rosijanka [135]
To start, let x represent the width and x+100 represent the length. Since the perimeter of a figure is the sum of all the measurements of the side which can be represented by (x+100)+(x+100)+x+x and since you know your perimeter is 1220, you can set the expression equal to 1220. This would look like this:
(x+100)+(x+100)+x+x=1220

Once you have done that, combine any like terms (combine terms with the same variables and raised to the same power together) which would simplify to this:
4x+200=1220

Now that you have your like terms simplified, subtract 200 from both sides to get 4x=1020 and finally, to solve for x, or find the width, divide both sides by 4 to get x=255.

Now that you have your width, now you must find your length as the question asks to find the dimensions of the rectangular field. To find the length, add 100 to the width, 255 since according to the information given, the length is 100 more than the width. When you add 100 to 255, you should get that your length is 355. 

Now that you have your length and width, you can conclude that the dimensions of the field is 255 by 355 feet, which is your answer :)
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Is there a second equation?
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