All categories

2 years ago

Domain And Range, Best answer will get brainliest

Mathematics

1 answer:

MrMuchimi2 years ago

7 0

Answer:

Domain is all the values that go into a function, and range are the values that come out of that function

Step-by-step explanation:

A value is an integer, so when you have an INPUT (your domain) that makes a line/slope, an OUTPUT (your range) will be your outcome, aka your answer

You might be interested in

The vertices of a triangle are A(4, 1), B(9, 1), C(2, 5). What is the area of this triangle.

kiruha [24]

Hey there!

$\large\boxed{10u^2}$

Formula for the area of a triangle is (1/2)bh.

Base of this triangle is 5, height is 4.

Image attached.

Plug values into the formula:

A = (1/2)(5)(4)

Simplify.

A = (1/2)(20)

A = 10

Area of the triangle is 10 units².

Hope this helps!

6 0

2 years ago

Read 2 more answers

A population of insects increases at a rate of 1.5% per day. About how long will it take the population to double?

never [62]

The <em><u>correct answer</u></em> is:

46.6 days

Explanation:

The general form for exponential growth is

$A=p(1+r)^t$ , where A is the total amount, p is the initial amount, r is the percent of growth, and t is the amount of time (in this case, days).

We do not know the initial amount, the total amount, or the amount of time. We do know that r, the percent of growth, is 1.5%; 1.5% = 1.5/100 = 0.015:

$A=p(1+0.015)^t$

We also know we want the total amount, A, to be twice that of the initial amount, p:

$2p = p(1+0.015)^t
\\
2p=p(1.015)^t$

Divide both sides by p:

$\frac{2p}{p}=\frac{p(1.015)^t}{p}
\\
\\ 2=1.015^t$

Using logarithms to solve this,

$\log_{1.015}(2)=t
\\
\\46.6=t$

8 0

3 years ago

Read 2 more answers

The putting together of two groups is called

den301095 [7]

It is called a bonding kilyodhuifguegdhegufguygfgerugued

4 0

3 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago

Help 4th grade math

Ymorist [56]

(32 + 18 + 13) / 3 = b

/ is divided by

you would add the boxes together and then divide them equally into the 3 displays

5 0

3 years ago

Read 2 more answers