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ASHA 777 [7]
3 years ago
10

At 6:00 the outside air temperature was 15°F. By 8:00 the temperature had dropped 9°F, and by 11:00 I had dropped another 12°. W

hat was the temperature at 11:00?
Mathematics
1 answer:
laila [671]3 years ago
8 0

Answer:

- 6°F

Step-by-step explanation:

Given :

Temperature at 6:00 = 15°F

Temperature dropped by 9°F by 8:00

Temperature by 8:00 = 15°F - 9°F = 6°F

Temperature dropped another 12°F by 11:00

Hence, Temperature at 11:00 will be :

6°F - 12°F = - 6°F

Temperature at 11:00 = - 6°F

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Hi there! :)

<u>Answer:</u>

Subtract 43 from 20 raised to the 7th power; then multiply by 3. The answer is: <u>3,839,999,871</u>

Step-by-step explanation:

"Subtract" means to take away a number from another.

" 20 raised to the 7th power" is the same thing as 20 exponent 7: 20^{7}


SO, you want to take away 43 from 20^{7} and then multiply the answer by 3:

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(1,280,000,000 - 43) × 3

1,280,000,000 - 43 = 1,279,999,957

1,279,999,957 × 3

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There you go! I really hope this helped, if there's anything just let me know! :)

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