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tigry1 [53]
3 years ago
12

What is negative eight plus four​

Mathematics
2 answers:
goldenfox [79]3 years ago
6 0

Answer:

-4

Step-by-step explanation:

- - - - - - - -

+ + + +

4 negatives cancel out and leave you with -4

sertanlavr [38]3 years ago
6 0

The answers is -8 + 4 = -4

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A rectangle has a height of 5 and a width of 4x2– 2x - 6.
joja [24]

Answer:

area = 20x^2 - 10x - 30

Step-by-step explanation:

5(4x2 - 2x - 6)

area = 20x^2 - 10x - 30

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3 years ago
Find x❤❤<br><br> I Will mark brainliest who answer first
andre [41]

Value of x is 35°

Step-by-step explanation:

  • Step 1: Since the line segment is a perpendicular bisector, the angle formed is equal to 90° and two triangles are also formed.

Find x using the property of triangles that sum of angles of a triangle is 180°

⇒ x° + 55° + 90° = 180°

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∴ x = 180 - 145 = 35°

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True or False question, I would say that it's true.
7 0
3 years ago
A nationwide study of American homeowners revealed that 65% have one or more lawn mowers. A lawnequipment manufacturer, located
GenaCL600 [577]

Answer:

z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589  

p_v =P(z>1.589)=0.056  

If we compare the p value obtained with the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

Step-by-step explanation:

Data given and notation

n=497 represent the random sample taken

X=340 represent the homes in Omaha with one or more lawn mowers

\hat p=\frac{340}{497}=0.684 estimated proportion of homes in Omaha with one or more lawn mowers

p_o=0.65 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the true proportion of homes in Omaha with one or more lawn mowers is higher than 0.65.:  

Null hypothesis:p\leq 0.65  

Alternative hypothesis:p > 0.65  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>1.589)=0.056  

If we compare the p value obtained with the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

7 0
3 years ago
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