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3 years ago

Please answer thanks

Mathematics

2 answers:

galina1969 [7]3 years ago

8 0

Answer:

Step-by-step explanation:

I believe it is answer a. the helicopter is the distance in the air that it is cruising and the angle is how it has to begin its decent down to the fireman

topjm [15]3 years ago

3 0

A is the answer next time use your calulator, but because you asked the answer will be .. a

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Factor 6w^4 + w^3 -3w^2

Shtirlitz [24]

6w^4+w³-3w²=w²(6w²+w-3)
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7 0

3 years ago

Find the value of x .. assume that segments that appear to be tangent are tangent .

Rus_ich [418]

Answer:

sqrt(277) =x

x is approximately 16.64331698

Step-by-step explanation:

This is a right triangle since 14 is tangent to the circle and 9 is a radius

We can use the Pythagorean theorem to solve this problem

a^2 +b^2 =c^2

9^2+14^2 =x^2

81+196 = x^2

277 = x^2

Taking the square root of each side

sqrt(277) = sqrt(x^2)

sqrt(277) =x

6 0

3 years ago

The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time

cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

$1\leq t\geq \sqrt{2}$

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

$h =20-5t^{2}$ -----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height $h = 15m$

Put height value in equation 1

$15 =20-5t^{2}$

$5t^{2} =20-15$

$5t^{2} =5$

$t^{2} =1$

$t =\pm1$

We know that the time is always positive, therefore $t=1$

when the stuntman is 10m above the ground.

height $h = 10m$

Put height value in equation 1

$10 =20-5t^{2}$

$5t^{2} =20-10$

$5t^{2} =10$

$t^{2} =\frac{10}{5}$

$t^{2} =2$

$t=\pm\sqrt{2}$

$t=\sqrt{2}$

Therefore ,time interval of camera film him is $1\leq t\geq \sqrt{2}$

7 0

4 years ago

Determine the intercepts of the line that correspond to the following table of values.

Dahasolnce [82]

We know that
to find the equation of a line i need two points

let
point A-----> (-21,10)
point B-----> (-28,14)

step 1
find the slope m
m=(y2-y1)/(x2-x1)-----> m=(14-10)/(-28+21)----> m=-4/7

step 2
find the equation of a line with
m=-4/7 and the point A (-21,10)
y-y1=m*(x-x1)------> y-10=(-4/7)*(x+21)---> y=(-4/7)x-12+10
y=(-4/7)x-2

step 3
find x intercept
for y=0
y=(-4/7)x-2------> 0=(-4/7)x-2-----> 4/7x=-2----> x=-14/4----> x=-3.5

the x intercept is (-3.5,0)

step 4
find the y intercept
for x=0
y=(-4/7)x-2--------> y=-2
the y intercept is (0,-2)

the answers are
the x intercept is (-3.5,0)
the y intercept is (0,-2)

see the attached figure

7 0

3 years ago

Solve for x. 89(54x−36)+2=−34(−40+16x)+90x

krok68 [10]

Eliminate parentheses using the distributive property.
4806x -3204 +2 = 1360 -544x +90x
5260x = 4562
x = 4562/5260
x = 2281/2630

7 0

3 years ago

Please answer thanks ​

Please answer thanks