What are the solutions of the equation x^4-5x-^2-14=0

1 answer:

8 0

So you want to start to factor so you get (x²+2)(x²-7) = 0. Now set each () to 0, so you get (x²+2) = 0 and (x²-7)=0. The first ends with +√2i and -√2i, the second ends with +√7 and -√7

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Step-by-step explanation:

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