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lys-0071 [83]
3 years ago
5

What are the solutions of the equation x^4-5x-^2-14=0

Mathematics
1 answer:
ohaa [14]3 years ago
8 0
So you want to start to factor  so you get (x²+2)(x²-7) = 0.  Now set each () to 0, so you get  (x²+2) = 0 and  (x²-7)=0.  The first ends with +√2i and -√2i, the second ends with +√7 and -√7
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Ne4ueva [31]
Find slope first:
m =y2-y1/x2-x1
m = 1--2/2--2
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Select a point, insert your slope, & put it into point slope form:
y-y1 =m(x-x1)

Your final answers are:

y-1=3/4(x-2)
OR
y+2 =3/4(x+2)
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Brandon has an action figure collection. He keeps 178 of the action figures on his wall, which is 89% of his entire collection.
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find the zeros of 2x^2 - 16x + 27 using the quadratic formula. be sure to simplify the expression. Can someone please show me ho
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For a quadratic of the form f(x)=ax^2+bx+c, we have the quadratic formula 
x=\dfrac{-b \pm \sqrt{b^2 -4ac}  }{2a},
where a is the coefficient (number before the variable) of the squared term, b is the coefficient of the linear term, and c is the constant term.

So, given 2x^2-16x+27=0, we can get that a=2, \ b=-16, and c=27. We substitute these numbers into the quadratic formula above.

x=\dfrac{-(-16) \pm \sqrt{(-16)^2 -4(2)(27)} }{2(2)}

x=\dfrac{16 \pm \sqrt{(256 -216)} }{4}

x=\dfrac{16 \pm \sqrt{40} }{4}

x=\dfrac{16 \pm 2\sqrt{10} }{4}

x=4+ \frac{\sqrt{10}}{2}, \ x=4- \frac{\sqrt{10}}{2}

This is our final answer.

If you've never seen the quadratic formula, you can derive it by completing the square for the general form of a quadratic. Note that the \pm symbol (read: plus or minus) represents the two possible distinct solutions, except for zero under the radical, which gives only one solution.
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