Question

Donnie is solving the equation 2x^2=27+3x with the quadratic formula. What values should he use for a , b , and c? A. a=2 b=27 c=3 B. a=2 b=-27 c=-3 C. a=2 b=3 c=27 D. a=2 b=-3 c=-27

Answer 1

Answer:

The value of a,b and c is:

              $a=2,\ b=-3\ \text{and}\ c=-27$

Step-by-step explanation:

We know that any quadratic equation is given by the form:

                     $ax^2+bx+c=0$

and the formula which gives the solution of the equation is given by:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here we have the equation as:

        $2x^2=27+3x$

which is also given by:

$2x^2-(27+3x)=0\\\\i.e.\\\\2x^2-27-3x\\\\2x^2-3x-27=0$

i.e. on comparing with the general quadratic formula we have:

$a=2,\ b=-3\ and\ c=-27$

Answer 2

Your answer is D. a = 2, b = -3, c = -27.
This is because to use the quadratic formula, your equation needs to equal 0, and to do that, you need to subtract 27 and 3x from the right to get 2x² - 3x - 27 = 0, and since the -3 is the x value, we use it for b.

I hope this helps!