Answer:
Point Critical point
Q (2,0) local minimum
R (-2,1) Saddle
S (2,-1) local maximum
T ( -2,-1) Saddle
O ( -2,0) Saddle
Step-by-step explanation: INCOMPLETE ANSWER INFORMATION ABOUT THE POINTS ARE RARE
f(x,y) = x³ +y⁴ - 6x -2y² +3
df/dx = f´(x) = 3x² -6x
df/dxdx = f´´(xx) = 6x
df/dy = f´(y) = -4y
df/dydy = 4
df/dydx = df/dxdy = 0
df/dydy = f´´(yy)
D = [ df/dxdx *df/dydy] - [df/dydx]²
D = (6x)*4 - 0
D = 6*2*4 D > 0 and the second derivative on x is 6*2 = 12
so D > 0 and df/dxdx >0 there is a local minimum in P
Q(2,1)
D = (6*2)*4 D>0 and second derivative on x is 6*2
The same condition there is a minimum in Q
R ( -2,1)
D = 6*(-2)*4 = -48 D< 0 there is a saddle point in R
S (2,-1)
D = 6*2*4 = 48 D > 0 and df/dxdx = 6*-1 = -6
There is a maximum in S
T ( -2,-1)
D = 6*(-2)*(4) = -48 D<0 there is a saddle point in T
O ( -2,0)
D = 6*(-2)*4 = -48 D<0 there is a saddle point in O
Answer:
what in the world is the first part
Step-by-step explanation:
Answer:
30
Step-by-step explanation:
25£ : 650 rubles
x£ : 780 rubles
25/x = 650/780
(cross multiply)
650x = 25×750
650x = 18 750
divide 18 750 by 650
which is = 30
thus x = 30
Answer:
Step-by-step explanation:
when 1/2 inch equals 4 feet the room is 2.25 inches, then
2 1/4 = 8/4 + 1/4 = 9/4
9/4 inches is the scale distance of the room
each 1/2 inch is 4 feet so divide 9/4 by 1/2 then multiply that by 4 to find the distance of the room
9/4 ÷ 1/2 = 9/4
9/4 * 2/1 = 18/4
18/4 = 9/2
9/2 * 4 feet = 9/2 * 4/1
9/2 * 4/1 = 36/2
36/2=18
the room is 18 feet across
then if the scale is 2/3 of an inch is 4 feet , then
2/3 * 9/4 = 18/12
18/12 = 3 inches is the scale size of Quinto's room
Answer:
you can use the quadratic formula to get theses:-
x =[-8 +/- sqrt(8^2 - 4*2*-3)] / 4
= -2 +/- sqrt88) / 4
= 0.35, -4.35 to nearest hundredth
Step-by-step explanation:
