A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
Learn more about translation rule:
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Answer:
h=7ft
Step-by-step explanation:
sinФ=opposite/hypotenuse
sin45°=5/h
0.71=5/h
multiply via by h
0.71h=(5/h)h
h cancel h it remains 5
0.71h=5
divide through by 0.71
0.71h/0.71=5/0.71
h=7.04ft
h=7ft approximately
Explanation :
What you would do is you take the area of the rectangle and subtract the area of the triangle
The area of a rectangle is Length * Width
Answer:
B.
Step-by-step explanation:
In the attached file
