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nordsb [41]
3 years ago
6

A watering can dispenses water at a rate of 0.40 gallon per minute. the original volume of water in the can was 10 gallons. whic

h set of ordered pairs shows the volume of water in the can in gallons (y) as a function of time in minutes (x) from the first minute after the can starts dispensing water? {(10, 1), (9.60, 2), (9.20, 3)} {(1, 10), (2, 9.60), (3, 9.20)} {(9.60, 1), (9.20, 2), (8.80, 3)} {(1, 9.60), (2, 9.20), (3, 8.80)}
Mathematics
2 answers:
kondor19780726 [428]3 years ago
8 0
The last one. because you are starting 1sec after the can has begun to pour. So, (1, 9.60) and the subsequent ordered pairs are correct
Juli2301 [7.4K]3 years ago
3 0

Answer:

The last one. because you are starting 1sec after the can has begun to pour. So, (1, 9.60) and the subsequent ordered pairs are correct

Step-by-step explanation:

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First, multiply 50*3 to get the answer in feet which is 150 ft.

Then, divide 150 ft by 60 which would be 2.5 ft per second.
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Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

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hoal

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