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patriot [66]
3 years ago
12

Ms abiola transferred 500$ from her savings account to a checking account on the 10th of the same month she made a deposit of 15

0$, payday was the 15th of March, Ms Abi's check of 148.50 was deposited the same day, she wrote a check of 157.25 all the other bills totaled to 1000$, these items were paid for from the checking account. What is the balance in her checking account at the end of March?
Mathematics
1 answer:
weqwewe [10]3 years ago
6 0

Answer: Balance = (X + 391.25) dollars.

Step-by-step explanation: Base on the information provided.

Let assume that Ms Biola initial amount in checking account = X

500 dollars was transferred into the account.

She made 150 dollars per day from 10th to 15th. I.e six day

150×6 = 900 dollars

148.5 dollars was also deposited

The Total amount

T = X + 500 + 900 + 148.5

= X + 1548.5

She wrote a check of 157.25 and settled Bill's of 1000 dollars

The balance at the end of March will be:

Balance = X + 1548.5 - 1157.25

Balance = (X + 391.25) dollars.

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Answer:

A. \sqrt{6x+9} +\sqrt{6x-9}

Step-by-step explanation:

We are given the functions f(x) and g(x) as,

f(x)=\sqrt{6x+9}

g(x)=\sqrt{6x-9}

It is required to find the function ( f+g ) i.e. ( f+g ) (x)

So, (f+g)(x)=f(x)+g(x)

i.e. (f+g)(x)=\sqrt{6x+9}+\sqrt{6x-9}

Hence, we get that (f+g)(x)=\sqrt{6x+9}+\sqrt{6x-9}.

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Consider an experiment where two 6-sided dice are rolled. We can describe the ordered sample space as below where the first coor
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Answer:

  • E = { (4,1) , (3,2) , (2,3) , (1,4) }
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Step-by-step explanation:

Let's start writing the sample space for this experiment :

S= { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event E ⇒

E : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from S ⇒

E = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate P(E) we are going to divide all the cases favorables to E over the total cases from S. We can do this because all 36 of these possible outcomes from S are equally likely. ⇒

P(E)=\frac{4}{36}=\frac{1}{9} ⇒

P(E)=\frac{1}{9}

Finally we are going to define the event F ⇒

F : '' The number of the first die is exactly 1 more than the number on the second die ''

⇒

F = { (2,1) , (3,2) , (4,3) , (5,4) , (6,5) }

Now given two events A and B ⇒

P ( A ∩ B ) = P(A,B)

We define the conditional probability as

P(A|B)=\frac{P(A,B)}{P(B)} with P(B)>0

We need to find P(F|E) therefore we can apply the conditional probability equation :

P(F|E)=\frac{P(F,E)}{P(E)}   (I)

We calculate P(E)=\frac{1}{9} at the beginning of the question. We only need P(F,E).

Looking at the sets E and F we find that (3,2) is the unique result which is in both sets. Therefore is 1 result over the 36 possible results. ⇒

P(F,E)=\frac{1}{36}

Replacing both probabilities calculated in (I) :

P(F|E)=\frac{P(F,E)}{P(E)}=\frac{\frac{1}{36}}{\frac{1}{9}}=\frac{1}{4}=0.25

We find out that P(F|E)=\frac{1}{4}=0.25

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the answer would be 408


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----  =  ----

102      ?


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