Two equally frequent gametes containing only parental allele combinations and no recombinant gametes
Answer:
a selective medium, a differential medium, and a complex medium
Explanation:
EMB Agar (Eosin Methylene Blue Agar) is both a selective and differential culture medium that slightly inhibits Gram-positive bacteria and can be used to distinguish bacteria capable of fermenting lactose from those that are unable to ferment this disaccharide. This medium is commonly used for isolation and differentiation of coliforms (i.e., bacteria found in the soil and water samples) and fecal coliforms (bacteria found in the gut and feces samples). In EMB agar, lactose-fermenting-gram-negative bacteria (e.g., <em>E. coli</em>) will form colored colonies, while non-lactose-fermenting-gram-negative bacteria will form colorless colonies (e.g., <em>Salmonella</em>). EMB agar is composed of lactose, gelatin, methylene blue dye and eosin Y dye ( a xanthene dye)
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Answer:
t = ln (N/N°)/(-0.0239)
Explanation :
The decay law is represented as
N = N°e^-kt
Where N is the final number of atom,
N° is the initial number of atoms
k is the decay constant
t is the half-life.
From the above we have,
N/N° = e^-kt
take ln of both sides
ln (N/N°) = -kt
t = ln(N/N°)/-k
At half life, N/N° = 1/2
Therefore, t = (ln 1/2)/-k
t = -0.693/-k
But t = 29 sec
29 = -0.693/-k
k = 0.0239 s^-1
Therefore,
The formula will be
t = ln (N/N°)/(-0.0239)
