13.5 / 0.75 = 18.....the grocer can make 18 of the 0.75 bags of candy with 0 lbs remaining....ur answer is A
Here I'll help you:
In order to solve the problem we must take the "x" to one side, and the numbers to the other side. When we move the three to the other side of the equation, we must change the "negative" to a positive [if it were to be positive, we'd make it negative.]
Now we have: 5 + 3 = 15x
Let's solve the left side.
We'll have: 8 = 15x
Now we have to divide both sides by 15.
Our answer would be:
.5333333 = 1x
In short, your answer is: X = 5.333333
The basic idea is that multiplying by 10 just moves the decimal point one place to the right. It makes the number bigger.
Examples:
3.1 x 10 = 31
3.1 x 10 x 10 = 31 x 10 = 310
Each time you multiply by another 10, the decimal point moves one more place.
In your exercise,
says you're going to multiply by 10 <u>three</u> times in a row. So that will move the decimal point 3 places to the right.
So what do you get if you move the decimal in 4.25 three places to the right?
For this case we must simplify the following expression:![7 (\sqrt [3] {2x}) - 3 (\sqrt [3] {16x}) - 3 (\sqrt [3] {8x})](https://tex.z-dn.net/?f=7%20%28%5Csqrt%20%5B3%5D%20%7B2x%7D%29%20-%203%20%28%5Csqrt%20%5B3%5D%20%7B16x%7D%29%20-%203%20%28%5Csqrt%20%5B3%5D%20%7B8x%7D%29)
We rewrite:

We rewrite the expression:
![7 (\sqrt [3] {2x}) - 3 (\sqrt [3] {2 ^ 3 * 2x}) - 3 (\sqrt [3] {2 ^ 3 * x}) =](https://tex.z-dn.net/?f=7%20%28%5Csqrt%20%5B3%5D%20%7B2x%7D%29%20-%203%20%28%5Csqrt%20%5B3%5D%20%7B2%20%5E%203%20%2A%202x%7D%29%20-%203%20%28%5Csqrt%20%5B3%5D%20%7B2%20%5E%203%20%2A%20x%7D%29%20%3D)
By definition of properties of powers and roots we have:
![\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20m%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bm%7D%20%7Bn%7D%7D)
Then, taking the terms of the radical:
![7 (\sqrt [3] {2x}) - 3 (2 \sqrt [3] {2x}) - 3 (2 \sqrt [3] {x}) =\\7 \sqrt [3] {2x} -6 \sqrt [3] {2x} -6 \sqrt [3] {x} =](https://tex.z-dn.net/?f=7%20%28%5Csqrt%20%5B3%5D%20%7B2x%7D%29%20-%203%20%282%20%5Csqrt%20%5B3%5D%20%7B2x%7D%29%20-%203%20%282%20%5Csqrt%20%5B3%5D%20%7Bx%7D%29%20%3D%5C%5C7%20%5Csqrt%20%5B3%5D%20%7B2x%7D%20-6%20%5Csqrt%20%5B3%5D%20%7B2x%7D%20-6%20%5Csqrt%20%5B3%5D%20%7Bx%7D%20%3D)
We add similar terms:
![\sqrt [3] {2x} -6 \sqrt [3] {x}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B2x%7D%20-6%20%5Csqrt%20%5B3%5D%20%7Bx%7D)
Answer:
Option C
Here are the steps, hope it helps!