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SIZIF [17.4K]
3 years ago
10

How do you find the sides of a trangle when you already have your hypotenuses

Mathematics
1 answer:
PIT_PIT [208]3 years ago
8 0

Answer

just reverse it. if you already have the long side plug it into the equation a2+b2=c2. and instead of adding youd subtract

Step-by-step explanation:

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Anyone know the answer to to this algebra question?
liraira [26]

Answer:

a=1

b= 1/16

c= 1/256

d= 1

e= 4/9

f= 16/81

Step-by-step explanation:

Plug in the values of X on the left side of the table into the function on the right side of the table. Remember that negative exponents mean the number is under a fraction. 4^-0 is like saying one over 4^0.

For the blue table, because the numbers are already in a fraction and in parentheses, you apply the exponent to each number individually.

7 0
3 years ago
Kwans The Kenningy account balance was $20 his ending balance is zero dollars what integer represents the changing in his accoun
77julia77 [94]

The integer number that represents the changing in his account balance from beginning to end is of -20.

<h3>Which numbers belong to the set of integer numbers?</h3>

Non-decimal numbers, either positive or negative numbers, also zero, belong to the set, which can be represented by:

Z = {..., -3, -2, -1, 0, 1, 2, 3, ...}

A change can be represented by the <u>final value subtracted by the initial value</u>. For this problem, we have that:

  • The initial balance is of $20.
  • The final balance is of $0.

Hence the change in the balance is:

0 - 20 = -20.

And the integer is -20.

More can be learned about integer numbers are brainly.com/question/17405059

#SPJ1

6 0
1 year ago
Hello<br>can you help me solve a question?<br>​
ICE Princess25 [194]

Answer:

Yes

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
For 0 ≤ ϴ &lt; 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va
Black_prince [1.1K]

Answer:

3 solutions:

\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is tan(\frac{\theta}{2}) so let's focus on that part of the equation first.

We know that:

tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}

therefore:

cos(\frac{\theta}{2})\neq0

so we need to find the angles that will make the cos function equal to zero. So we get:

cos(\frac{\theta}{2})=0

\frac{\theta}{2}=cos^{-1}(0)

\frac{\theta}{2}=\frac{\pi}{2}+\pi n

or

\theta=\pi+2\pi n

we can now start plugging values in for n:

\theta=\pi+2\pi (0)=\pi

if we plugged any value greater than 0, we would end up with an angle that is greater than 2\pi so,  that's the only angle we cannot include in our answer set, so:

\theta\neq \pi

having said this, we can now start solving the equation:

tan(\frac{\theta}{2})=sin(\theta)

we can start solving this equation by using the half angle formula, such a formula tells us the following:

tan(\frac{\theta}{2})=\frac{1-cos(\theta)}{sin(\theta)}

so we can substitute it into our equation:

\frac{1-cos(\theta)}{sin(\theta)}=sin(\theta)

we can now multiply both sides of the equation by sin(\theta)

so we get:

1-cos(\theta)=sin^{2}(\theta)

we can use the pythagorean identity to rewrite sin^{2}(\theta) in terms of cos:

sin^{2}(\theta)=1-cos^{2}(\theta)

so we get:

1-cos(\theta)=1-cos^{2}(\theta)

we can subtract a 1 from both sides of the equation so we end up with:

-cos(\theta)=-cos^{2}(\theta)

and we can now add cos^{2}(\theta)

to both sides of the equation so we get:

cos^{2}(\theta)-cos(\theta)=0

and we can solve this equation by factoring. We can factor cos(\theta) to get:

cos(\theta)(cos(\theta)-1)=0

and we can use the zero product property to solve this, so we get two equations:

Equation 1:

cos(\theta)=0

\theta=cos^{-1}(0)

\theta={\frac{\pi}{2}, \frac{3\pi}{2}}

Equation 2:

cos(\theta)-1=0

we add a 1 to both sides of the equation so we get:

cos(\theta)=1

\theta=cos^{-1}(1)

\theta=0

so we end up with three answers to this equation:

\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}

7 0
2 years ago
The area of the triangle below is 8.91 square inches. What is the length of the base?<br> 2.2 in
Inessa05 [86]

Answer:

8.1

Step-by-step explanation:

Area of a triangle = ½ × base × height = Area

Rearranged =

area/1/2xheight

The base is the length.

8.91/1/2x2.2

=8.1 inches

4 0
2 years ago
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