How many different arrangements can be made from the letters

Moscow, the capital city of Russia, is at 37.62 degrees longitude and 55.75 degrees latitude. Brasilia, the capital city of Braz

Vsevolod [243]

Answer:

drfcexdw

Step-by-step explanation:

8 0

2 years ago

5#The distribution of scores on a standardized aptitude test is approximately normal with a mean of 480 and a standard deviation

kirza4 [7]

We want to find the value that makes

$P(X\ge x)=0.2$

To find it we must look at the standard normal table, using the complementary cumulative table we find that

$P(Z\ge z)=0.20045\Leftrightarrow z=0.84$

Then, using the z-score we can find the minimum score needed, remember that

$z=\frac{x-\mu}{\sigma}$

Where

σ = standard deviation

μ = mean

And in our example, x = minimum score needed, therefore

$\begin{gathered} 0.84=\frac{x-480}{105} \\ \\ x=0.84\cdot105+480 \\ \\ x=568.2 \end{gathered}$

Rounding to the nearest integer the minimum score needed is 568, if you get 568 you are at the top 20.1%.

7 0

1 year ago

Mai's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Mai $4.10 per pound, and type B co

velikii [3]

About 49 pounds

$5.75 x 2 = 11.50

561.60 / 11.50 = 48.83 (round)
49 lbs

7 0

2 years ago

Miki has 104 nickels and 88 dimes. She wants to divide her coins into groups where each group has the same number of nickels and

pochemuha

Given :

Miki has 104 nickels and 88 dimes.

She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.

To Find :

Largest number of groups she can have .

Solution :

In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .

Now , factorizing both of them , we get :

$104=1\times 2\times 2\times 2\times 13$

$88=1\times 2\times 2\times 2\times 11$

Form above , we can say that common factors are :

$HCF=2\times 2\times 2=8$

Therefore , the largest number of groups she can have is 8 .

Hence , this is the required solution .

6 0

3 years ago

Read 2 more answers

Solve the following ODE's: c) y* - 9y' + 18y = t^2

Nastasia [14]

Answer:

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

m² - 3 m - 6 m+ 18 = 0

(m-3)(m-6) = 0

m = 3,6

C.F. = $C_1e^{3t}+C_2e^{6t}$

now calculating P.I.

$P.I. = \frac{t^2}{D^2 - 9D +18}$

$P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

hence the complete solution

y = C.F. + P.I.

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

7 0

2 years ago