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Lyrx [107]
3 years ago
10

What is an equivalent fraction for 3:11

Mathematics
1 answer:
Dmitry [639]3 years ago
8 0

Answer:

\frac{3}{11}

Step-by-step explanation:

When you have something like that, just think that the first number goes on top and the second number goes on bottom.

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Find the length of the third side to the nearest 10th
katovenus [111]

Answer:

9.5

Step-by-step explanation:

Using the pythagorean theorem a^2+b^2=c^2, we can say that 3^2+b^2=10^2.

Simplify and you get 9+b^2=100. Subtract 9 from both sides and you get b^2=91. When you take the square root you get 9.53939... round to the nearest tenth and the missing side is 9.5.

3 0
3 years ago
Each face of a pyramid is an isosceles triangle with a 82° vertex angle. What are the measures of the base​ angles? PLZ help
Gnesinka [82]
Base=(180°-vertex)/2=(180-82)/2=98/2=49°

base angles are 49°
3 0
4 years ago
Pls help me with this. Show your work and solve that is it.
Minchanka [31]

Answer:

5\sqrt{18}-\sqrt{32} \\=5 \sqrt{3 \times 3 \times 2}  -  \sqrt{2 \times 2 \times 2 \times 2 \times 2}  \\  = 5 \times 3 \times  \sqrt{2}  - 2 \times 2 \times  \sqrt{2}  \\  = 15 \sqrt{2}  - 4 \sqrt{2}  \\  =  \boxed{11 \sqrt{2} }

<h3>11√2 is the right answer.</h3>
8 0
3 years ago
Y = –1/2x + 4
torisob [31]
Y = -1/2x + 4....sub in -1/2x + 4 in for y in the other equation

x + 2y = -8
x + 2(-1/2x + 4) = -8
x - x + 8 = -8
x - x = -8 -8
0 = -16...incorrect....NO SOLUTIONS

5 0
3 years ago
Read 2 more answers
If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t2.
Zina [86]

Answer: (a) (i)50.42 m/s (ii) 51.35 m/s (iii) 52.094 m/s (iv) 52.2614 m/s (v) 52.27814 m/s

(b) 54.14 m/s

Step-by-step explanation:

The average speed over the given time interval [a,b]: = \frac{y(b)-y(a)}{b-a}

Given: If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t^2.

(a)

(i) average speed = \frac{y(2)-y(1)}{2-1}

=\frac{56(2)-1.86(2)^2-(56(1)-1.86(1)^2)}{1}

=50.42 m/s

(ii) average speed = \frac{y(1.5)-y(1)}{1.5-1}

=\frac{56(1.5)-1.86(1.5)^2-(56(1)-1.86(1)^2)}{0.5}

=51.35m/s

(iii) average speed = \frac{y(1.1)-y(1)}{1.1-1}

=\frac{56(1.1)-1.86(1.1)^2-(56(1)-1.86(1)^2)}{0.1}

=52.094m/s

(iv) average speed = \frac{y(1.01)-y(1)}{1.01-01}

=\frac{56(1.01)-1.86(1.01)^2-(56(1)-1.86(1)^2)}{0.01}

=52.2614&#10;m/s

(v) average speed = \frac{y(1.001)-y(1)}{1.001-01}

=\frac{56(1.001)-1.86(1.001)^2-(56(1)-1.86(1)^2)}{0.001}

=52.27814&#10;m/s

(b) y(1)=56(1)-1.86(1)^2

=56-1.86

= 54.14 m/s

3 0
3 years ago
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