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4 years ago

May someone please help me?

Mathematics

1 answer:

Irina-Kira [14]4 years ago

6 0

What's the question Love? I can't help til i know the question =/

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Brainliest and 30 points please help

kolbaska11 [484]

Answer:

22. Perimeter = 52 units

Area = 160 Square Units

23. Notation form : $2 \times 10^{5}$

Standard Form : 200000

Step-by-step explanation:

22.

The formula for perimeter is

P = 2 (length + Width )

= 2 ( 2x+3x+1)

= 2(5x+1)

The Formula for Area of a rectangle is

A= length x width

A= $2x \times (3x+1)$

A= $6x^2+2x$

Now we have to find the Perimeter and Area for x = 5

P = 2(5 x 5 +1)

P= 2(26)

P=52 units

A= 6 x 5 x 5 + 2 x 5

A= 150 + 10

A= 160 square units

23.

A. By using rule of exponents , we can determine that both the results will be same.

Miriam's calculation

$\frac{2.8 \times 10^{9}}{1.4 \times 10^{4}}$

$\frac{2.8}{1.4} \times 10^{9-4}$

$2 \times 10^5$

Priya's calculation

$\frac{2.8 \times 10^{2}}{1.4 \times 10^{-3}}$

$\frac{2.8}{1.4} \times 10^{2-(-3)}$

$2 \times 10^5$

Standard notation

$2 \times 10^5 = 200000$

4 0

3 years ago

Fracciones equivalente 1/4

stealth61 [152]

2/4 esa es una ojalá y pude contestar a tiempo

6 0

3 years ago

2. Faith opens a credit card with an APR of 16.50% compounded monthly. How much is charged in interest this month if her

FromTheMoon [43]

Answer:

14.44 (Letter D)

Step-by-step explanation:

The answer is 14.44

Hopefully its correct!!!

8 0

2 years ago

Given: JP = KP; PX = PY<br> Prove: APYJ - APXK<br> Which best describes the missing reasons?

Alex73 [517]

Answer:

SAS Reflective property

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

3 years ago