Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25.
1 answer:
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Answer:
4(90) + 4(2)
Step-by-step explanation:
The given expression is 4(92)
This can be expressed as
This can also be expressed as
Using the distributive law of multiplication and additon,
a*(b+c) = a*b + a*c
In this case a=4
b=90 and c = 2
So the equivalent expression is
But this is the same as option 2 in the list of given options.
Hence the equivalent expression is 4(90) + 4(2)