Answer:
a. 95% confidence interval estimate for the population mean amount of paint included in a 1-gallon can is 0.998±0.0055
b. <u>No,</u> because a 1-gallon paint can containing exactly 1-gallon of paint lies <u>within</u> the 95% confidence interval.
c. Yes. The population amount of paint per can is assumed normally distributed, because confidence interval calculations assume normal distribution of the parameter.
d. 90% confidence interval is 0.998±0.0046. The answer in b. didn't change; 1-gallon paint can containing exactly 1-gallon of paint lies <u>within</u> the 90% confidence interval. The manager <u>doesn't have</u> a right to complain to the manufacturer.
Step-by-step explanation:
Confidence Interval can be calculated using M±ME where
M is the sample mean amount of paint per 1-gallon can (0.998 gallon)
ME is the margin of error from the mean
And margin of error (ME) can be calculated using the equation
ME=
where
- z is the corresponding statistic in the 95% confidence level (1.96)
- s is the sample standard deviation (0.02 gallon)
- N is the sample size (50)
Then ME=
≈0.0055
95% confidence interval is 0.998±0.0055
90% confidence interval can be calculated similary, only z statistic is 1.64.
ME=
≈0.0046
90% confidence interval is 0.998±0.0046
72
Add them all up = 48+9+15
Answer:
There are 10 possible ways the student can schedule the three classes
Step-by-step explanation:
The college student is choosing 3 classes to take during the first, second, and third semester from 5 electives.
Therefore, the student is choosing 3 items from a total of 5 and the order is not of key concern here. This is thus a combination problem;
5C3 = 10
read as 5 choose 3
The above mathematical operation can be performed using any modern calculator.
<span> If two secants intersect from a point outside of the circle, then you can use formula:
26(26 + d) = 22(22 + 40)
676 + 26d = 22 * 62
26d = 1364 - 676
26d = 688
d = 688/26
d = 26.5 </span>← to the nearest tenth
Answer:
? We don't see any graphs to choose from
Step-by-step explanation:
Graph a dotted line (to show it's not included) with y-intercept 1 and slope 1/2. Test the origin (0, 0) in the inequality:
This is true, so shade the side of the line that the origin is on (above the line).
Next inequality...
Graph a solid line with y=intercept 1 and slope 1. Test the origin.
True! Shade the side of the line the origin is on (below the line). See image2, attached.
Graph a dotted line with y-intercept -1 and slope -2. Test the origin (0, 0).
True, so shade the side the origin is on (above the line).
The solutions are located where all the shadings intersect. See image3. The solutions are above the red line, above the green line and below the blue line.
