Since each vector is a member of

, the vectors will span

if they form a basis for

, which requires that they be linearly independent of one another.
To show this, you have to establish that the only linear combination of the three vectors

that gives the zero vector

occurs for scalars

.

Solving this, you'll find that

, so the vectors are indeed linearly independent, thus forming a basis for

and therefore they must span

.
2-1=1-1=0-1=-1 is the first 2 part of the eqation too then it will be 2-2=0-1=-1-1=-2-1=-3
-3
Answer:

Step-by-step explanation:
Rewrite the differential equation as:

Integrate both sides with respect to x:


Integrate one more time both sides with respect to x:


Now that we find the solution, let's find its derivate:

Evaluating the initial conditions:


Replacing the value of the constants that we found in the differential equation solution:

Answer:
61
Step-by-step explanation:
84+38=122
180-122=58
DBC=58
180-58=122
122÷2=61
61+58=119
180-119=61
Answer: 0
Yurrrrrrr
Step-by-step explanation: