Well, I don't really understand if it is 30 or 305 because of the spacing but I'll answer both. If it is 5y+305, just divide the whole equation by 5 and it will look like this (<u>5y+305)</u> then the factor would be 5(y+61)<u>
</u> 5
If it is 5y+30 it would be just in the same process, Divide the equation by 5 and the result will be 5(y+6).
Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
The solution to this equation is x = 0 or x = 1
To find the solution, you use Desmos and enter x+2 in both one and 2^x+1 in box two. It will graph the lines for you and you take the x-coordinate of the two places where the lines overlap, and they overlap at (0,2) and (1,3).
10% of 80 = 8
80 - 8 = 72
if they are 10% off, the contact lenses will cost $72
Answer:
A. b(w) = 80w +30
B. input: weeks; output: flowers that bloomed
C. 2830
Step-by-step explanation:
<h3>Part A:</h3>
For f(s) = 2s +30, and s(w) = 40w, the composite function f(s(w)) is ...
b(w) = f(s(w)) = 2(40w) +30
b(w) = 80w +30 . . . . . . blooms over w weeks
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<h3>Part B:</h3>
The input units of f(s) are <em>seeds</em>. The output units are <em>flowers</em>.
The input units of s(w) are <em>weeks</em>. The output units are <em>seeds</em>.
Then the function b(w) above has input units of <em>weeks</em>, and output units of <em>flowers</em> (blooms).
__
<h3>Part C:</h3>
For 35 weeks, the number of flowers that bloomed is ...
b(35) = 80(35) +30 = 2830 . . . . flowers bloomed over 35 weeks
