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myrzilka [38]
3 years ago
10

PLEASE HELP ME!!!

Mathematics
2 answers:
sineoko [7]3 years ago
4 0

Answer:

A

Step-by-step explanation:

The behavior is learned by the offspring, taught by the parents

Marrrta [24]3 years ago
3 0

Answer:

uh I think should be a

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Mathematics
Vladimir [108]

Answer:

there no data

Step-by-step explanation:

Find the median of the first and third quartiles81, 69 ,90, 79, 59, 125, 95, 116, 183, 97, 92, 50, 122, 55, 9250, 55, 59, 69, 79, 81, 90,   92,     92, 95, 97, 116, 122, 125, 183.The first quartile: 50, 55, 59, 69, 79, 81, 90: median of the first quartile is 69The third quartile: 92, 95, 97, 116, 122, 125, 183: median of the third quartile is 116.The interquartile range is the difference between the median of both the first and third quartile:  which is 116 - 69 = 47.There are no outliers in this set of data

4 0
1 year ago
Find the arc length of the partial circle.
Kay [80]

Answer:

12.42 units

Step by step explanation:

Given,

length of the radius = 2 units

Therefore, arc length of the complete circle = 2 × 3.14 × 2 units = 12.56 units

Therefore, arc length of the partial circle = 3/4 × 12.56 units

= 12.42 units

3 0
3 years ago
GIVING BRAINLIEST!!! Which function grows at the fastest rate for increasing values of x? YOU CAN CHOOSE MORE THAN 1 BTW
Leno4ka [110]
Is b is 5x^2 then b would be the correct answer.
6 0
3 years ago
Read 2 more answers
A square outdoor patio with side length x feet is surrounded by a brick walkway that is 4 feet wide. What is the area of the wal
Masja [62]

Answer:

Area of walkway = 16(x+4) ft^{2}

Step-by-step explanation:

Length of the sides of the square outdoor = x feet

Area of the square outdoor = length x length

                            = x * x

                            = x^{2} ft^{2}

The square outdoor is surrounded by 4 feet of walkway. So that,

length of the walkway = (x + 2(4))

                                     = (x + 8)

Area of walkway with outdoor = (x + 8)*(x + 8)

                                      = (x^{2} + 16x + 64) ft^{2}

Area of walkway = Area of walkway with outdoor - Area of the square outdoor

                            = ( x^{2} + 16x + 64) - x^{2}

                            = 16x + 64

Area of walkway = 16(x+4) ft^{2}

7 0
3 years ago
Anyone please help me it is a very simple question:
leonid [27]
Try this;

6£(x) + 6£(x+3)
4 0
3 years ago
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