The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
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Answer:
142 sq cm
Step-by-step explanation:
You find the areas of each face, using area of a rectangle (length * width), to get: 7*3+7*3+7*5+7*5+3*5+3*5=21+21+35+35+15+15=<u>142</u>
Answer:
is 63.65
Step-by-step explanation:
but whit the tax i think is 64
Answer:
Step-by-step explanation:
Let the number = x
3x + 9 = 2x - 6 Looks like you are going to get something negative here.
Subtract 2x from both sides.
3x - 2x + 9 = 2x - 2x - 6
x + 9 = -6
Subtract 9 from both sides.
x + 9 - 9 = - 6 - 9
Combine
x = - 15
Answer:
it is 3,100
Step-by-step explanation:
bc you cant round up 0 so your answer is 3.100