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3 years ago

If x^2+2=3^2/3+3^-2/3 then prove that 3x^3+9x-8=0

Mathematics

1 answer:

Mama L [17]3 years ago

5 0

here it is

hope it helps

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F(x)= 2x/x+1 use long division to rewrite

PSYCHO15rus [73]

The Answer is : 2- 2/x+1

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3 years ago

Order the steps to show how to solve the equation 2(4x−11)+9=192(4x−11)+9=19.

Blababa [14]

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3 years ago

2.8 = 2y What does y equal? 1.4 0.5 2.8 0.6

igor_vitrenko [27]

Answer: 1.4

Step-by-step explanation: First, swap the sides of the equation so that the one with the variable can be in front.

So, its 2y=2.8

To solve this, you simply divide both sides of the equation by 2.

2 divided by 2 is 0. That leaves you with the y by itself. Then, 2.8 divided by 2 is 1.4

So, y=1.4

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3 years ago

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On a scale drawing, a bicycle is 6 4/5 inches tall. The scale factor is 1/6. Find the height of the bicycle

Fantom [35]

The height will be six times what is on the drawing.

6 4/5 x 6 = 36 24/5 = 40 4/5 inches tall.

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3 years ago

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

marissa [1.9K]

Complete question:

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

what is the area of the sector?

Answer:

The area of the sector = $\frac{\pi}{2}$ square units

Step-by-step explanation:

To find the area of the sector of a circle, let's use the formula:

$A = \frac{1}{2} r^2 \theta$

Where, A = area

r = radius = 3

$\theta = \frac{1}{9}\pi$

Substituting values in the formula, we have:

$A = \frac{1}{2}*3^2* \frac{1}{9}\pi$

$A = \frac{1}{2}*9* \frac{1}{9}\pi$

$A = 4.5 * \frac{1}{9}\pi$

$A = \frac{\pi}{2}$

The area of the sector = $\frac{\pi}{2}$ square units

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3 years ago

If x^2+2=3^2/3+3^-2/3 then prove that 3x^3+9x-8=0​

If x^2+2=3^2/3+3^-2/3 then prove that 3x^3+9x-8=0