The domain for N is All integers where n ≥ 1
<u>Solution:</u>
According to statement a1 = 2 and r = 4. This shows that r is greater than 1.
If r is greater than 1 than it includes integers greater than 1 or equal to 1. It does not include all the real numbers because real numbers include negative numbers also.
If starting value is 2, if we put n=0, then we get 2, but if we put a negative value than we would get a number which is not a part of our sequence.
Thus the domain of n is All integers where n greater than or equal to 1
Answer:
<em> n = 13 </em>
Step-by-step explanation:
= 
+ (n - 1)d
= 3 + 7(n - 1) (for the first AP)
= 63 + 2(n - 1) ( for the second one)
3 + 7(n - 1) = 63 + 2(n - 1)
3 + 7n - 7 = 63 + 2n - 2
5n = 65
<em>n = 13</em>
the first step is to isolate A which gets 39.59a+45=44.99
now get A and only A
39.59a=-.1
now divide both sides by 39.59 getting A= -0.00252589
X - 3 < 9 or x + 5 ≥ 10
+ 3 + 3 - 5 - 5
x < 12 or x ≥ 5
Solution Set: {x|x < 12 or x ≥ 5}, (-∞, 12) or (5, ∞)
Answer:
A
Step-by-step explanation:
We know that negative numbers are smaller than positive numbers, so let's compare the 2 negative numbers. Unlike positive numbers, the more negative it has, the smaller it is. So we know the smallest is -20. Without looking at the other numbers (even though I did just in case) we know that this is correct. They say least to greatest, so -20 should be first. A is the only one that starts with -20.
