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ANTONII [103]
3 years ago
14

what is 63/15 in mixed numbers? what is 96/7 in mixed numbers?what is 210/20 In mixed numbers? what is 209/18 in mixed numbers ?

what is 624/60 in mixed numbers?
Mathematics
2 answers:
Archy [21]3 years ago
4 0
1. 4 1/5
2. 10 1/2
3. 11 11/18
4. 10 2/5
Hope I helped.
RUDIKE [14]3 years ago
4 0

Answer:

1. 4\:\frac{1}{5}

2. 10\:\frac{1}{2}

3. 11\:\frac{11}{18}

4. 10\:\frac{2}{5}

and \frac{624}{60}=10\frac{24}{60}

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2.3 is the other length
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8 0
3 years ago
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I am offering another 100 points
Ivahew [28]

Answer:

\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.

Step-by-step explanation:

<u>Perfect squares</u>: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find \sf \sqrt{75} , identify the perfect squares immediately <u>before</u> and <u>after</u> 75:

  • 64 and 81

\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}

\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.

See the attachment for the correct placement of \sf \sqrt{75} on the number line.

6 0
1 year ago
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A laptop is in the shape of a rectangular prism. The laptop has a length of 14 inches, a width of 10 inches, and a height of 1 i
Aleks04 [339]

Answer:

140 inches

Step-by-step explanation:

The formula for volume or a rectangular prism is v=lwh

Length = 14

Width= 10

Height= 1

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6 0
3 years ago
A central angle of a circle measures 1.5 radians. If the radius of the circle is 3 cm, what is the area of the related sector?
soldi70 [24.7K]

Answer:

Option B. 6.75\ cm^{2}

Step-by-step explanation:

we know that

The area of a circle is equal to

A=\pi r^{2}

we have

r=3\ cm

substitute

A=\pi (3^{2})=9 \pi\ cm^{2}

Remember that

2\pi radians subtends the complete circle of area 9 \pi\ cm^{2}

so

by proportion

Find the area of the related sector for a central angle of 1.5 radians

Let

x------> the area of the related sector

\frac{9 \pi}{2\pi}\frac{cm^{2}}{radians} =\frac{x}{1.5}\frac{cm^{2}}{radians}\\ \\x=9*1.5/2\\ \\x= 6.75\ cm^{2}

7 0
3 years ago
=(1,2,3,4,5,6,7,8,9,10,11,12)
kati45 [8]

Answer:

2 and 4 is overlapping :)

Step-by-step explanation:

square numbers only those two

and even numbers=2,4,6,8,10,12

:)

8 0
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