9514 1404 393
Answer:
∠CAB = 28°
∠DAC = 64°
Step-by-step explanation:
What you do in each case is make use of the relationships you know about angles in a triangle and around parallel lines. You can also use the relationships you know about diagonals in a rectangle, and the triangles they create.
<u>Left</u>
Take advantage of the fact that ∆AEB is isosceles, so the angles at A and B in that triangle are the same. If we call that angle measure x, then we have the sum of angles in that triangle is ...
x + x + ∠AEB = 180°
2x = 180° -124° = 56°
x = 28°
The measure of angle CAB is 28°.
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<u>Right</u>
Sides AD and BC are parallel, so diagonal AC can be considered a transversal. The two angles we're concerned with are alternate interior angles, so are congruent.
∠BCA = ∠DAC = 64°
The measure of angle DAC is 64°.
(Another way to look at this is that triangles BCE and DAE are congruent isosceles triangles, so corresponding angles are congruent.)
Answer:
10.6 units
Step-by-step explanation:
distance formula
= √((x2-x1)²+(y2-y1)²)
= √((5+3)²+(-6-1)²
= √(8²+(-7)²)
= √ (64+49)
= √113
= 10.6
I'm assuming you meant 5:4 and 27 students.
5 parts girls to every 4 parts boys. To work this out you first need to find one part;
5+4=9
27÷9=3
1 part = 3 people
5 parts are girls, so;
3x5 = 15
there are 15 girls
