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2 years ago

Solve negative 2.5 minus 2.5

Mathematics

2 answers:

Oksana_A [137]2 years ago

7 0

If you're doing subtraction it should be zero

Scilla [17]2 years ago

5 0

The answer is -5. Hope it helps.

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At a restaurant the bill was $35.10 with a 15% tip added on. How much is the total bill, rounded to the nearest whole cent?

blondinia [14]

Answer:

15% = 0.15

35.10 * (1 + 0.15) = $40.37

7 0

2 years ago

EASY MATH QUESTIONS<br><br> NEED HELP

Nikitich [7]

Answer:

f(6) = -14

Step-by-step explanation:

x = -6

f(x) = x^2/3 - 2

f(-6) = (-6)^2/3 -2 Replace x with the given number

= -36/3 - 2 Simplify -6 to the power of 2

= - 12 - 2 Divide -36 by 3

f(6) = - 14 Subtract -2 from -12

8 0

2 years ago

Read 2 more answers

A model of a tractor is shaped like a rectangle prism and has a width of 3in and the length 11 and the height 4 the scale of the

qwelly [4]

I think it is 33, according to the scale. 1:33 means one cubic inch of the model represents 33 cubic inches of the actual tractor. Agree?

7 0

2 years ago

Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then

olchik [2.2K]

Answer:

It is proved that $\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Step-by-step explanation:

Given vector field,

$F=P\uvec{i}+Q\uvec{j}+R\uvec{k}$

Where,

$P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}$

To show,

$\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Consider,

$\frac{\partial P}{\partial y}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial y\partial x}=\frac{\partial^2 f}{\partial x\partial y}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial y})=\frac{\partial Q}{\partial x}$

$\frac{\partial P}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial z\partial x}=\frac{\partial^2 f}{\partial x\partial z}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial x}$

$\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}$