Answer
(x - 4)
Step by step explanation
To find the factors, plug in the x values in the given equation and see which value of x makes the equation equal to zero.
Here (x - 4) is a factor.
Therefore, x = 4
when we plug in x = 4 in the given expression, we get zero.
Let's check it out.
3(4)^3 + 8 (4)^2 - 87(4) + 28
192 + 128 - 348 + 28
348 - 348
0
The answer is (x - 4)
Thank you.
Answer:
The data set with the greater range is the Girls
The greater median is the Girls at 110
Step-by-step explanation:
The range is the difference between the largest and smallest values.
As the largest value for the boys is 120 and the smallest is 60, the range would be 60
As the largest value for the girls is 150 and the smallest is 70, the range would be 80.
This means that the Girls have the greater range
The median is the number in the middle when the data is in ascending order.
As we have an even number, we will have to find the middle value between 5 and 6. To do this, we can add them together and divide them by 2.
The 5th boy in ascending order is 90 and the 6th boy is 90.

The 5th 5irl is 100 and the 6th girl is 120

This means that the median is greater for the Girls.
Well this problem can be solved with Algebra
the rule here is that for every incrementing sequence you increase your number by 6.
T(n)=18+6(n-1)
for 603 to be in the sequence, it has to male sense with the function above
603=18+6(n-1)
603-18=585
585=6(n-1)
n-1=(585/6)
n=(585+6)/6
n=591/6
here is your answer.
This equals [f(3) - f(1)] / [3-1]
= 3^2 + 6(3) + 10 - (1^2 + 6(1) + 10) / 2
= (37 - 17) / 2
= 10 Answer
Answer:
10.1%
Step-by-step explanation:
The first thing we should do is calculate the total volume of the solution when mixing them would be:
0.7 + 0.3 = 1
Now, we have that the resulting concentration (x) would be equal to the sum of the multiplications between the volumes and the concentrations to be mixed, as follows:
x * 1 = 0.7 * 0.05 + 0.3 * 0.22
x = 0.035 + 0.066
x = 0.101
That is, the concentration of the resulting mixture would be 10.1% (0.101 * 100)