If y=2cos(x/2) then d^2y/dx^2 =

1 answer:

5 0

We first need dy/dx.

dy/dx = -2sin(x/2)(1/2)

dy/dx = -sin(x/2)

We now find d^2y/dx^2.

d^2y/dx^2 = -cos(x/2)(1/2)

d^2y/dx^2 = -(1/2)cos(x/2)

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Select the graph that shows the solution set for the following system.<br> x + y < 2<br> x>2

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Answer:

Answer is in the attachment.

Step-by-step explanation:

To graph x>2 consider first x=2. x=2 is a vertical line and if you want to graph x>2 you need to shade to the right of the vertical line.

To graph x+y<2, I will solve for y first.

x+y<2

Subtract x on both sides:

y<-x+2

Consider the equation y=-x+2. This is an equation with y-intercept 2 and slope -1 or -1/1. So the line you have in that picture looks good for y=-x+2. Now going back to consider y<-x+2 means we want to shade below the line because we had y<.

Now where you see both shadings will be intersection of the shadings and will actually by your answer to system of inequalities you have. In my picture it is where you have both blue and pink.

I have a graph in the picture that shows the solution.

Also both of your lines will be solid because your question in the picture shows they both have equal signs along with those inequality signs.

Just in case my one graph was confusing, I put a second attachment with just the solution to the system.