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satela [25.4K]
3 years ago
9

How would I find the slope intercept form of x+y+3=0?

Mathematics
1 answer:
denis-greek [22]3 years ago
4 0
Slope-intercept form follows the formula: y=mx+ b

To find the slope intercept form of those, you need to isolate y
For example, x + y + 3 = 0. Subtract 3 and x to get y=-x-3 and that is your slope intercept form! Simple as that :)
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Answer:

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Step-by-step explanation:

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your bike lock has 4 digits numbered 0 to 9. find the total number of possible outcomes for the bike lock
Ann [662]

Answer:

There could be many, my estimate would be around 100.

Step-by-step explanation:

It may sound exaggerated but it can be.

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3 years ago
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3 years ago
Write a polynomial that has a GCF of 7m and another with a GCF of 2ab squared.
SVEN [57.7K]

The polynomial that has a GCF of 7m is 14mn - 21m + 49m²n + 7mn²

The polynomial that has a GCF of 2ab² is 6a²b² - 8ab³ + 4a³b² + 2a³b³

<h3>Writing Polynomials </h3>

From the question, we are to write a polynomial that has a GCF of 7m

That is,

We are to write a polynomial that has a greatest common factor of 7m

<em>Writing the polynomial</em>

14mn - 21m + 49m²n + 7mn²

The  polynomial above has a greatest common factor of 7m. That is, 7m is the greatest factor that can divide each of the terms

We are to write a polynomial with a GCF of 2ab²

<em />

<em>Writing the polynomial</em>

6a²b² - 8ab³ + 4a³b² + 2a³b³

The polynomial above has a greatest common factor of 2ab². That is, 2ab² is the greatest factor that can divide each of the terms

Hence,

The polynomial that has a GCF of 7m is 14mn - 21m + 49m²n + 7mn²

The polynomial that has a GCF of 2ab² is 6a²b² - 8ab³ + 4a³b² + 2a³b³

Learn more on Writing polynomials here: brainly.com/question/4525973

#SPJ1

7 0
1 year ago
Liz simplified the expression 5x - 3(4 - x) and got 2x -12. Did she simplify the expression correctly? Explain how you know.
Orlov [11]

Answer:

Step-by-step explanation:

Incorrect. She forgot to change the sign while distributing.

5x - 3(4-x) = 5x - 12 + 3x = 8x - 12

5 0
3 years ago
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