3 years ago

What is the constant of proportionality, and what method did you use to determine this?

Mathematics

1 answer:

atroni [7]3 years ago

8 0

Answer:

it should be A

Step-by-step explanation:

hope this helps :)

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Step-by-step explanation:

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Answer:

$\large\boxed{n=\dfrac{27}{20}}$

Step-by-step explanation:

$\text{Let}\ n\ \text{is a number.}\\\\\text{The product of a number and}\ -\dfrac{2}{3}\ \text{is}\ -\dfrac{9}{10}:\\\\-\dfrac{2}{3}\cdot n=-\dfrac{9}{10}\\\\-\dfrac{2n}{3}=-\dfrac{9}{10}\qquad\text{change the signs}\\\\\dfrac{2n}{3}=\dfrac{9}{10}\qquad\text{cross multiply}\\\\(2n)(10)=(3)(9)\\\\20n=27\qquad\text{divide both sides by 20}\\\\\dfrac{20n}{20}=\dfrac{27}{20}\\\\\boxed{n=\dfrac{27}{20}}$

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When triangles are similar, ratios of corresponding side lengths are the same. The side lengths you know are CD, DU, VW, WU. (You also know CU, but you do not know the corresponding length VU.)

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is the answer. I hope it will help you.

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