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mylen [45]
3 years ago
7

What is x over two plus three greater than 9 equals

Mathematics
1 answer:
MArishka [77]3 years ago
8 0
X/2 + 3 > 9
Subtract 3 from both sides
x/2 > 6
Multiply 2 on both sides
Final Answer: x > 12
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An expression that represents repeated multiplication of the same factor<span> is called a </span>power<span>. The </span>number<span> 5 is called the base, and the </span>number<span> 2 is called the exponent. The exponent corresponds to the </span>number<span> of times the base is </span><span>used as a factor</span>
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What is the value of a, b, and c in the quadratic equation -2x^2+4x-3=0
amm1812
A = -2
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0.7(3s+4)−1.1s=7.9 I need a answer
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First, expand the bracket

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3 years ago
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The table below shows the radius y, in inches, created by growing algae in x days: Time (x) (days) 1 4 7 10 Radius (y) (inches)
tatuchka [14]
PART A:
Given the table below showing the radius y, in inches, created by growing algae in x days.

Time (x) (days):          1       4        7        10
Radius (y) (inches):    1       8       11       12

We can find the find the correlation coeficient of the data using the table below:
\begin{center}&#10;\begin{tabular}&#10;{|c|c|c|c|c|}&#10;x & y & x^2 & y^2 & xy \\ [1ex]&#10;1 & 1 & 1 & 1 & 1\\&#10;4 & 8 & 16 & 64 & 32\\&#10;7 & 11 & 49 & 121 & 77\\&#10;10 & 12 & 100 & 144 & 120\\ [1ex]&#10;\Sigma x=22 & \Sigma y=32 & \Sigma x^2=166 & \Sigma y^2=330 & \Sigma xy=230&#10;\end{tabular}&#10;\end{center}

Recall that the correlation coefitient is given by the equation:
r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{ \sqrt{(n\Sigma x^2-(\Sigma x)^2)(n\Sigma y^2-(\Sigma y)^2)} }  \\  \\ = \frac{4(230)-(22)(32)}{ \sqrt{(4(166)-(22)^2)(4(330)-(32)^2)} } = \frac{920-704}{ \sqrt{(664-484)(1,320-1,024)}}  \\  \\ = \frac{216}{ \sqrt{180(296)}} = \frac{216}{ \sqrt{53,280} } = \frac{216}{230.8} =0.94

[Notice: even without using the formular to find the value of the correlation coeficient, it can be seen that the value of y strictly increases as the valu of x increases. This means that the value of the correlation coeficient is closer to +1 and from the options the value that is closest to +1 is 0.94]

From the value of the correlation coeffeicient, it can be deduced that the radius of the algae has a strong positive relationship with the time.

Recall the for the value of the correlation coeficient closer to +1, the relationship is strong positive, for the value closer to -1, the value is strong negative and for the values closer to zero, either way of zero is a weak positive if it is positive and weak negative if it is negative.


PART B:
Recall that the slope of a straight line passing through two points
(x_1,y_1) and (x_2,y_2)
is given by
m= \frac{y_2-y_1}{x_2-x_1}

Thus the slope of the graph of radius versus time between 4 and 7 days, [i.e. the line passes through points (4, 8) and (7, 11)] is given by
m= \frac{11-8}{7-4}= \frac{3}{3} =1

The value of the slope means that the radius of the algea grows by 1 inch evry day between day 4 and day 7.


PART C:
We can say that the data above represent both correlation and causationg.

Recall that correlation expresses the relationship between two variables while causation expresses that an event is as a result of another event.

From the information above, we have seen that there is a relationship (correlation) between the passing of days and the growth in the radius of the algae.

Also we can conclude that the growth in the radius of algae is a function of the passing of days, i.e. the growth in the radius of algae is as a result of the passing of days.

Therefore, <span>the data in the table represent both correlation and causation.</span>
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