What is the value of a, b, and c in the quadratic equation -2x^2+4x-3=0
2 answers:
Remember the quadratic equation is in the genreal form of ax^2 + bx + c = 0. So a, b, and c, are the respective coefficients. In your problem the a is -2, b is 4, and c is -3.
A = -2 b = 4 c = -3 They are the coefficients to the terms in the equation<span />
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19 is
A: real
B: whole
C: integer
D: rational
I think the answer is D hope this helps
Answer:
r1= -3
r2= (11/2)
Step-by-step explanation:
5-4r=17
-4r=17-5
-4r=12
r=13
and
5-4r=-17
-4r=-22
r= 11/2
Answer
-64
just use ur calculator since my teacher let us use the calculator i just typed in 16.(-4) and got -64
Answer:
16%
Step-by-step explanation:
20/125 = 0.16
0.16 x 100 = 16% (multiply by 100 to get a percentage)